最常用的 Java 8 中的 Lambda 函数(项目中实用笔记)

简介

Java 8 中的新特性，虽然现在都出到了Java14版本，不过在日常的开发过程中，8的版本是足够使用了，再说现在的8以上的版本也都面向商业收费了，很多新手，我所接触到的，像我那时候一样，追求船新版本，一上来就去学java14的东西，当成一个爱好还行，重心还是要放在实用上

过滤

需求：我需要过滤高考分数大于500的人

首先，新建一个内部类

    static class Student{
        private String name;
        private Integer score;

        public String getName() {
            return name;
        }

        public void setName(String name) {
            this.name = name!=null ? name.trim() : null;
        }

        public Integer getScore() {
            return score;
        }

        public void setScore(Integer score) {
            this.score = score;
        }

        public Student(String name, Integer score) {
            this.name = name;
            this.score = score;
        }

        @Override
        public String toString() {
            return "Student{" +
                    "name='" + name + '\'' +
                    ", score=" + score +
                    "}\n";
        }
    }

使用IntStream遍历快速初始化一批值

    public static void main(String[] args) {
      List<Student> studentList =  IntStream.rangeClosed(0,20)
                .mapToObj(i -> new Student("Java Pro"+i,490+i))
                .collect(Collectors.toList());
    }

过滤出分数大于500的并输出

        List<Student> studentGiao = studentList.stream()
              .filter(student -> student.score > 500)
              .collect(Collectors.toList());
        System.out.println(studentGiao.toString());

输出：

[Student{name='Java Pro11', score=501}
, Student{name='Java Pro12', score=502}
, Student{name='Java Pro13', score=503}
, Student{name='Java Pro14', score=504}
, Student{name='Java Pro15', score=505}
, Student{name='Java Pro16', score=506}
, Student{name='Java Pro17', score=507}
, Student{name='Java Pro18', score=508}
, Student{name='Java Pro19', score=509}
, Student{name='Java Pro20', score=510}
]

日常求和

需要考虑到为空和为0的情况

package com.github.gleans;

import java.util.Arrays;
import java.util.List;
import java.util.Objects;

public class LambdaLearning {
    public static void main(String[] args) {
        List<Double> nums = Arrays.asList(1.01, 2.11, 3.23, 4.222, null, 5.6);
        double resNum = nums.stream()
                .map(num -> Objects.isNull(num) ? 0 : num)
                .mapToDouble(num -> num)
                .sum();
        System.out.println(resNum);
    }
}

map是重新指向一个对象，把->右侧的对象赋予，此处判断若num为null则赋予0值
注意，这里不可给null使用filter过滤掉，否则全为null的情况，会报空指针异常

扩展计算

    public static void testTwo(){
        List<Double> nums = Arrays.asList(1.01, 2.11, 3.23, 4.222, null, 5.6);
        DoubleSummaryStatistics number = nums.stream()
                .map(num -> Objects.isNull(num) ? 0 : num)
                .mapToDouble(num -> num)
                .summaryStatistics();
        System.out.println("最大值:"+number.getMax());
        System.out.println("最小值:"+number.getMin());
        System.out.println("平均值:"+number.getAverage());
    }

输出

最大值:5.6
最小值:0.0
平均值:2.6953333333333336

reduce简单使用

    public static void main(String[] args) {
        testOne();
    }

    public static void testOne(){
        List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6);
        // 这里的 10 相当于初始值
        int sum = numbers
                .stream()
                .reduce(10, Integer::sum);
        System.out.println(sum);
    }

Collectors.groupingBy

根据年龄分组

package com.github.gleans;

import java.math.BigDecimal;
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;

public class SumWage {
    public static void main(String[] args) {
        List<UserDemo> userDemoList = new ArrayList<UserDemo>() {{
            add(new UserDemo(20, "jason", BigDecimal.valueOf(1000000)));
            add(new UserDemo(22, "yasuo", BigDecimal.valueOf(2000000)));
            add(new UserDemo(22, "ekko", BigDecimal.valueOf(100)));
        }};
        Map<Integer, List<UserDemo>> UserDemoMapByAge = userDemoList.stream()
                .collect(Collectors.groupingBy(UserDemo::getAge));
        System.out.println(UserDemoMapByAge.toString());
    }

    static class UserDemo {
        private int age;
        private String username;
        private BigDecimal wage;

        public UserDemo(int age, String username, BigDecimal wage) {
            this.age = age;
            this.username = username;
            this.wage = wage;
        }

        public int getAge() {
            return age;
        }

        public void setAge(int age) {
            this.age = age;
        }

        public String getUsername() {
            return username;
        }

        public void setUsername(String username) {
            this.username = username;
        }

        public BigDecimal getWage() {
            return wage;
        }

        public void setWage(BigDecimal wage) {
            this.wage = wage;
        }

        @Override
        public String toString() {
            return "UserDemo{" +
                    "age=" + age +
                    ", username='" + username + '\'' +
                    ", wage=" + wage +
                    '}';
        }
    }
}

输出

{20=[UserDemo{age=20, username='jason', wage=1000000}], 22=[UserDemo{age=22, username='yasuo', wage=2000000}, UserDemo{age=22, username='ekko', wage=100}]}

json化观看观看更为直观

{
	20:[
		{
			"age":20,
			"username":"jason",
			"wage":1000000
		}
	],
	22:[
		{
			"age":22,
			"username":"yasuo",
			"wage":2000000
		},
		{
			"age":22,
			"username":"ekko",
			"wage":100
		}
	]
}

进阶计算 Collectors.summarizingDouble

Map<Integer, DoubleSummaryStatistics> userAvgWageByAge = userDemoList.stream()
                .collect(Collectors.groupingBy(UserDemo::getAge, Collectors.summarizingDouble(s -> s.getWage().doubleValue())));

userAvgWageByAge.forEach((k, v) -> System.out.println(String.format("年龄:%d,平均工资:%f", k, v.getAverage())));

数组快速转为List

Stream.of(1, 2, 3, 4).collect(Collectors.toList())

结论

后续会学习更多关于Lambda的操作，日积月累...一定会成为一个秃头的程序猿

标签：wage,username,Java,name,age,笔记,score,public,Lambda
来源： https://www.cnblogs.com/cvandy/p/13234511.html