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python实现圣诞树

作者:互联网

先来个迷你的 *_*

height = 5
stars = 1
for i in range(height):
    print((' ' * (height - i)) + ('*' * stars))
    stars += 2
print((' ' * height) + '|')



再整个花里胡哨的

import turtle
screen = turtle.Screen()
screen.setup(800,600)
circle = turtle.Turtle()
circle.shape('circle')
circle.color('red')
circle.speed('fastest')
circle.up()
square = turtle.Turtle()
square.shape('square')
square.color('green')
square.speed('fastest')
square.up()
circle.goto(0,280)
circle.stamp()
k = 0
for i in range(1, 17):
    y = 30*i
    for j in range(i-k):
        x = 30*j
        square.goto(x,-y+280)
        square.stamp()
        square.goto(-x,-y+280)
        square.stamp()
    if i % 4 == 0:
        x = 30*(j+1)
        circle.color('red')
        circle.goto(-x,-y+280)
        circle.stamp()
        circle.goto(x,-y+280)
        circle.stamp()
        k += 2
    if i % 4 == 3:
        x = 30*(j+1)
        circle.color('yellow')
        circle.goto(-x,-y+280)
        circle.stamp()
        circle.goto(x,-y+280)
        circle.stamp()
square.color('brown')
for i in range(17,20):
    y = 30*i
    for j in range(3):
        x = 30*j
        square.goto(x,-y+280)
        square.stamp()
        square.goto(-x,-y+280)
        square.stamp()
turtle.exitonclick()

标签:square,goto,python,30,实现,圣诞树,280,circle,stamp
来源: https://www.cnblogs.com/chenshifang/p/12077887.html