php-pdo定义一个函数,然后在select语句中使用它
作者:互联网
我的查询有点像这样:
CREATE FUNCTION func ... ;
SELECT * FROM ....;
我使用的是php的PDO,在$pdo-> query()中不允许使用超过1条语句,所以我决定将查询分为两部分,因此我使用$pdo执行CREATE FUNCTION查询-> exec(),然后在select语句上使用$pdo-> query().
但是,我在执行select语句时收到错误消息,即FUNCTION database.func不存在.我该如何解决?当我在phpmyadmin中将其作为单个查询运行时,它工作正常
编辑:PHP代码:
class MyClass {
function connectPDO($user,$pass,$chartset="utf8"){
//simple function for making a new PDO object and mysql connection
$dbname = "my_db";
try {
//creating new pdo
$pdo = new PDO('mysql:host=localhost;dbname='.$dbname, $user,$pass);
//attributes set to throw errors and exceptions which can be caught, can be changed
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
//fetch associative arrays
$pdo->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE,PDO::FETCH_ASSOC);
//default chartset
$pdo->exec('SET NAMES "'.$chartset.'"');
} catch (PDOException $e) {
//on some error
$output = "Ay caramba! there's something wrong here!.<br>";
echo $output.$e->getMessage();
exit();
}
$this->db = $pdo;
}
}
$object = new MyClass();
$object->connectPDO("user","pass");
$sqlPreliminary = "
DROP FUNCTION IF EXISTS myFunc;
DELIMITER //
CREATE FUNCTION myFunc (id INT)
RETURNS DECIMAL
BEGIN
RETURN id + 1;
END //
DELIMITER ;
";
$sqlFinal = "
SELECT id, myFunc(id) AS plusOne FROM table;
";
$object->db->exec($sqlPreliminary);
var_dump($object->db->query($sqlFinal)->fetchAll(PDO::FETCH_ASSOC));
解决方法:
使用PDO创建用户定义的函数仅由exec起作用,不需要定界符. $db是PDO实例.
$db->exec('CREATE FUNCTION ConvertHTMLToText(str LONGTEXT CHARSET utf8)
RETURNS LONGTEXT CHARSET utf8
BEGIN
DECLARE start, end INT DEFAULT 1;
LOOP
SET start = LOCATE("<", str, start);
IF (!start) THEN RETURN str; END IF;
SET end = LOCATE(">", str, start);
IF (!end) THEN SET end = start; END IF;
SET str = TRIM(INSERT(str, start, end - start + 1, ""));
END LOOP;
END');
标签:sql-function,sql,mysql,php,pdo 来源: https://codeday.me/bug/20191123/2065426.html