java-从一个活动向另一个活动发送多个意图

我对android非常陌生,我正在尝试将用户输入的数据(他们的名字)发送到另一个活动.过去,我能够使用Intent在活动之间发送单行代码,但是我无法解决如何向两个不同的TextView发送两个不同的字符串.

这是到目前为止我的MainActivity代码：

package com.example.game;

import android.content.Intent;
import android.os.Bundle;
import android.app.Activity;
import android.view.Menu;
import android.widget.Button;
import android.widget.EditText;
import android.view.View;
import android.widget.AutoCompleteTextView;

public class MainActivity extends Activity {
public final static String EXTRA_MESSAGE = "com.example.myfirstapp.MESSAGE";
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    Button button = (Button)findViewById(R.id.button);
    button.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            sendNames();
            sendNames2();
        }
    });
}


@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.main, menu);
    return true;
}
public void sendNames() {
    //sends player1's name to mainGame
    Intent intent = new Intent (this, MainGame.class);
    EditText player1 = (EditText) findViewById(R.id.player1);
    String message = player1.getText().toString();
    intent.putExtra(EXTRA_MESSAGE, message);
    startActivity(intent);
}//sends player2's name to mainGame
 public void sendNames2(){
    Intent intent2 = new Intent(this, MainGame.class);
    EditText player2 = (EditText) findViewById(R.id.player2);
    String message2 = player2.getText().toString();
    intent2.putExtra(EXTRA_MESSAGE, message2);
    startActivity(intent2);
}
}

我第二项活动MainGame的代码：

package com.example.game;

import android.content.Intent;
import android.os.Bundle;
import android.app.Activity;
import android.view.Menu;
import android.annotation.SuppressLint;
import android.view.MenuItem;
import android.support.v4.app.NavUtils;
import android.annotation.TargetApi;
import android.os.Build;
import android.widget.TextView;

public class MainGame extends Activity {
@SuppressLint("NewAPI")
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_game);
    //retrives player1's name
    Intent intent = getIntent();
    String message = intent.getStringExtra(MainActivity.EXTRA_MESSAGE);
    TextView name1 = (TextView) findViewById(R.id.name1);
    name1.setText(message);
    //retrivews player2's name
    Intent intent2 = getIntent();
    String message2 = intent2.getStringExtra(MainActivity.EXTRA_MESSAGE);
    TextView name2 = (TextView) findViewById(R.id.name2);
    name2.setText(message2);

    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.HONEYCOMB) {
        getActionBar().setDisplayHomeAsUpEnabled(true);
    }

}

       return super.onOptionsItemSelected(item);
}

}

当我运行它时,我得到了两个TextView中都为“ name2”添加的内容.我需要做些什么来改变这个？

解决方法:

when i run this i get whatever has been put in for ‘name2’ in both TextView’s

这是因为您正在使用第二个Intent创建Activity的新实例.您可以通过不同的方式来做到这一点.一个方法是创建一个Intent作为成员变量,在您的第一个函数调用中实例化它,添加额外功能,然后在第二个方法中添加另一个额外功能,然后在此处调用startActivity.

但是同时进行所有操作可能会更容易且更具可读性.

 public void sendNames() {
    //sends player1's name to mainGame
    Intent intent = new Intent (this, MainGame.class);
    EditText player1 = (EditText) findViewById(R.id.player1);
    String player1Name= player1.getText().toString();
    intent.putExtra("player1Name", player1Name);
    EditText player2 = (EditText) findViewById(R.id.player2);
    String player2Name= player2.getText().toString();
    intent2.putExtra("player2Name", player2Name);
    startActivity(intent);

只需调用此方法即可.

然后用

Intent intent = getIntent();
String name1 = intent.getStringExtra("player1Name");
TextView name1 = (TextView) findViewById(R.id.name1);
name1.setText(message);

String name1 = intent2.getStringExtra("player2Name");
TextView name2 = (TextView) findViewById(R.id.name2);
name2.setText(name1 ;

标签：android-studio,android-intent,java,android
来源： https://codeday.me/bug/20191122/2063456.html