PHP-Symfony 3：提交表单后设置值

我有一个表单集合,并希望在提交表单后根据field1的值设置field2. field2在表单中不可编辑,但必填.

我尝试了每个FormEvent(FormEvents：:),但收到错误消息：

SQLSTATE[23000]: Integrity constraint violation: 1048 Column ‘field2’ cannot be null

// AppBundle/Form/MyFormType.php

// ...
$builder->addEventListener(FormEvents::POST_SUBMIT, function(FormEvent $even) {
    $data = $event->getData();
    $form = $event->getForm();

    if (isset($data['field1'])) { // isset
        $field2 = $this->container->get('repository')->find($data['field1'])->getValue(); // service works

        $data['field2'] = $field2; // !!! doesn't work !!!              
        $data->setField2($field2); // !!! doesn't work !!!    
    }
});

我究竟做错了什么？提前致谢！

解决方法:

试试这个代替

use Symfony\Component\Form\FormEvents;

$builder->addEventListener(FormEvents::PRE_SUBMIT, function(FormEvent $event) {
    $data = $event->getData();
    $form = $event->getForm();

    if (isset($data['field1'])) {
        $field2 = $this->container->get('repository')->find($data['field1'])->getValue();

        $data['field2'] = $field2;              
        $event->setData($data); 
    }
});

标签：symfony,symfony-forms,php
来源： https://codeday.me/bug/20191118/2026629.html