php-在设置值之前检查请求输入是否不为null
作者:互联网
我有一个可以设置用户设置的API.因为这两个输入都不是强制性的,所以我想先检查该值是否存在,然后将其设置为模型属性,以避免出现空值.
$this->InputValidator->validate($request, [
'firsname' => 'string',
'lastname' => 'string',
'email' => 'email',
'mobile_phone' => 'string',
'address' => 'string',
'language' => 'string',
'timezone' => 'string',
'nationality' => 'string',
'profile_photo' => 'url'
]);
$userInformation = new UserInformation([
'firstname' => $request->input('firstname'),
'lastname' => $request->input('lastname'),
'email' => $request->input('email'),
'mobile_phone' => $request->input('mobile_phone'),
'address' => $request->input('address'),
'profile_photo' => $request->input('profile_photo')
]);
$User->information()->save($userInformation);
具体来说,当输入之一不存在时,我不想将其传递给模型.我也不想输入
解决方法:
做这个
$userInformation = new UserInformation;
if(request->has('firstname')){
$userInformation->firstname = $request->firstname;
}
if(request->has('lastnme')){
$userInformation->lastname = $request->lastname;
}
// do it for all
$User->information()->save($userInformation);
编辑:或使用表单请求,这是一个更好的方法
标签:lumen,laravel,eloquent,null,php 来源: https://codeday.me/bug/20191118/2024527.html