javascript-通过在React Native中获取来设置状态

在我的React Native应用程序中,我试图从我的API中获取特定的响应字符串,并将其显示在视图中的文本组件中.下面的方法不起作用,并返回“ TypeError：undefined不是函数(正在评估_this5.setState …)

我认为这很简单,但却使我难以理解.

export default class Test extends Component {

  constructor (props) {
    super(props);
    this.state = {
      current: 'Blank',
    }
  }

  render () {
    return (
      <View>
        {this.state.current}  
      </View>   
    );
  }

  postRequest (data) {
    fetch('https://????/controllers/ajaxController.php', {
      method: 'POST',
      headers: {
        'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8',
      },
      body: "main=" + parseInt(data),
    })
    .then(function (response) {
      responseData = response.json();
      if (response.status == 200) {
        return responseData.then((data) => this.setState({ current: data[0] }));
      }  else {
        throw new Error('Server Error!');
      }
    })
  }
}

解决方法:

使用箭头函数可以将此词法范围限定于组件：

postRequest = (data) => {
  fetch('https://????/controllers/ajaxController.php', {
    method: 'POST',
    headers: {
      'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8',
    },
    body: "main=" + parseInt(data),
  })
  .then((response) => {
    responseData = response.json();
    if (response.status == 200) {
      return responseData.then((data) => this.setState({ current: data[0] }));
    } else {
      throw new Error('Server Error!');
    }
  })
}

标签：reactjs,react-native,react-native-android,javascript
来源： https://codeday.me/bug/20191111/2019264.html