c#-将XML部分反序列化为对象
作者:互联网
我有一些反序列化为业务对象的XML.我正在使用XmlSerializer.Deserialize这样做.但是,我希望XML中包含的XmlElement之一保留为XElement.
由于XElement不可序列化,因此无法直接完成(使用XmlElementAttribute).我还尝试将该元素序列化为字符串(分两步尝试获取XElement),但是由于错误而失败:
unexpected node type element.
readelementstring method can only be
called on elements with simple or
empty content
知道如何做到吗?
这是xml和我想要的结果对象的示例:
<Person name="Joe">
<Hobbies>
<Hobby name="Reading" .../>
<Hobby name="Photography" .../>
</Hobbies>
<HomeAddress>
...
</HomeAddress>
</Person>
宾语:
public class Person
{
[XmlAttribute("Name")]
public string Name {get; set;}
?????
public XElement Hobbies {get; set;}
[XmlElement("HomeAddress")]
public Address HomeAddress {get; set;}
}
无效的尝试:
[XmlElement("Hobbies")]
public XElement Hobbies {get; set;}
[XmlElement("Hobbies")]
public string Hobbies {get; set;}
解决方法:
为了避免像IXmlSerializable之类的东西的辛苦工作,您可以按照半隐藏的传递XmlElement属性的方式进行操作.但是请注意,这不能完全满足您的要求,因为您只能有一个根XElement值(根据您的示例,不能为两个);你需要一个清单来做到这一点…
using System;
using System.ComponentModel;
using System.Xml;
using System.Xml.Linq;
using System.Xml.Serialization;
public class Person
{
[XmlAttribute("Name")]
public string Name { get; set; }
[XmlIgnore]
public XElement Hobbies { get; set; }
[XmlElement("Hobbies")]
[Browsable(false), EditorBrowsable(EditorBrowsableState.Never)]
public XmlElement HobbiesSerialized
{
get
{
XElement hobbies = Hobbies;
if(hobbies == null) return null;
XmlDocument doc = new XmlDocument();
doc.LoadXml(hobbies.ToString());
return doc.DocumentElement;
}
set
{
Hobbies = value == null ? null
: XElement.Parse(value.OuterXml);
}
}
[XmlElement("HomeAddress")]
public Address HomeAddress { get; set; }
}
public class Address { }
static class Progmam
{
static void Main()
{
var p = new Person { Hobbies = new XElement("xml", new XAttribute("hi","there")) };
var ser = new XmlSerializer(p.GetType());
ser.Serialize(Console.Out, p);
}
}
标签:xelement,serialization,xml,c 来源: https://codeday.me/bug/20191106/2001812.html