Java弹出按钮
作者:互联网
注意:您可能必须编译并运行我的示例才能完全理解我的问题.如果不是犹太洁食,我事先表示歉意.
我试图创建一个基于JToggleButton和JPopupMenu的Swing控件.
如果弹出菜单可见,则选择切换按钮;如果弹出菜单不可见,则取消选择切换按钮.因此,该行为类似于JComboBox,不同之处在于弹出窗口可以包含任意组件.
下面的代码是如何创建控件的示例(除了它将在其自己的类中,例如JPopupToggleButton之类).不幸的是,它在不同的外观和感觉下表现出不同的行为(我已经用Metal和Nimbus对其进行了测试).
此处发布的代码在Metal中表现出预期的效果,但在Nimbus中却表现不佳.使用Nimbus时,只需反复单击切换按钮即可显示和隐藏弹出窗口,您将明白我的意思.
import java.awt.BorderLayout;
import java.awt.Dimension;
import java.awt.MouseInfo;
import java.awt.Point;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.*;
import javax.swing.event.PopupMenuEvent;
import javax.swing.event.PopupMenuListener;
public class PopupButtonExample extends JFrame
{
public static void main( String[] args )
{
java.awt.EventQueue.invokeLater( new Runnable()
{
@Override
public void run()
{
PopupButtonExample example = new PopupButtonExample();
example.setDefaultCloseOperation( JFrame.EXIT_ON_CLOSE );
example.setVisible( true );
}
});
}
public PopupButtonExample()
{
super( "Components in Popup" );
JPanel popupPanel = new JPanel();
popupPanel.setLayout( new BorderLayout() );
popupPanel.add( new JLabel( "This popup has components" ),
BorderLayout.NORTH );
popupPanel.add( new JTextArea( "Some text", 15, 20 ),
BorderLayout.CENTER );
popupPanel.add( new JSlider(), BorderLayout.SOUTH );
final JPopupMenu popupMenu = new JPopupMenu();
popupMenu.add( popupPanel );
final JToggleButton popupButton = new JToggleButton( "Show Popup" );
popupButton.addActionListener( new ActionListener()
{
@Override
public void actionPerformed(ActionEvent e)
{
if( popupButton.isSelected() )
popupMenu.show( popupButton, 0, popupButton.getHeight() );
}
});
popupMenu.addPopupMenuListener( new PopupMenuListener()
{
@Override
public void popupMenuWillBecomeVisible(PopupMenuEvent pme) {}
@Override
public void popupMenuCanceled(PopupMenuEvent pme) {}
@Override
public void popupMenuWillBecomeInvisible(PopupMenuEvent pme) {
Point mouseLoc = MouseInfo.getPointerInfo().getLocation();
Point componentLoc = popupButton.getLocationOnScreen();
mouseLoc.x -= componentLoc.x;
mouseLoc.y -= componentLoc.y;
if( !popupButton.contains( mouseLoc ) )
popupButton.setSelected( false );
}
});
JPanel toolBarPanel = new JPanel();
toolBarPanel.add( popupButton );
JToolBar toolBar = new JToolBar();
toolBar.add( toolBarPanel );
setLayout( new BorderLayout() );
add( toolBar, BorderLayout.PAGE_START );
setPreferredSize( new Dimension( 640, 480 ) );
pack();
}
}
区分以下几行可使代码在Nimbus中表现出预期的效果,但在Metal中却表现出预期.同样,只要继续单击切换按钮,即可查看我的意思.
// Point mouseLoc = MouseInfo.getPointerInfo().getLocation();
// Point componentLoc = popupButton.getLocationOnScreen();
// mouseLoc.x -= componentLoc.x;
// mouseLoc.y -= componentLoc.y;
// if( !popupButton.contains( mouseLoc ) )
所以这是我的两个问题:
(1)在Nimbus中,为什么隐藏弹出面板的单击没有像Metal那样传递到切换按钮?
(2)如何解决这个问题,使其在所有外观上都可以使用?
解决方法:
> Nimbus过于越野车(并且开发在中间终止),与Metal相比,我需要三下鼠标单击JToggleButton
>每个标准L&F都有其特定的问题,尤其是SystemLookAndFeel
>使用JWindow而不是JPopup,因为JPopup也存在另一个Bug,例如带有JCombobox的JPopup
标签:look-and-feel,swing,nimbus,jpopupmenu,java 来源: https://codeday.me/bug/20191101/1986332.html