javascript-无法从sinon.js fakeServer中触发对$.ajax的调用

我有以下茉莉花规格：

describe "plugins", ->
    beforeEach ->
    @server = sinon.fakeServer.create()

    afterEach ->
    @server.restore()

    describe "reviewStatus", ->
    it "should attach dates to content", ->
      @server.respondWith("GET", "/GeneralDocument.mvc.aspx/GetDocumentParent?typeName=ncontinuity2.core.domain.Plan&documentParentUid=45f0bccb-27c9-410a-bca8-9ff900ab4c28d",
        [200, {"Content-Type": "application/json"},
        '{"ReviewDate":"22/09/2012","AcknowledgedDate":"05/07/2012"}'])   

      $('#jasmine_content').addReviewStatus('ncontinuity2.domain.Plan', "45f0bccb-27c9-410a-bca8-9ff900ab4c28")     

      @server.respond()

      expect($('#reviewDateTab').find("strong").eq(0).length).toEqual(1)

addReviewStatus是我编写的jQuery插件：

do($= jQuery) ->
    $.fn.extend
        addReviewStatus: (type, uid) ->
            ele = @

            reviewData = null           

            getJSON '/GeneralDocument.mvc.aspx/GetDocumentParent', {typeName: type, documentParentUid: uid}, 
                                (document) ->
                                    console.log('document = ' + document)
                                    compileTemplate(ele, document)
                                (response) ->
                                    showErrorMessage resonse.responseText
#etc., etc.

上面的getJSON方法像这样调用$.ajax：

function getJSON(url, params, ajaxCallBack, ajaxErrorHandler, excludeProgress){
    var e = (ajaxErrorHandler) ? ajaxErrorHandler : validationErrorCallBack;
    var s = (ajaxCallBack) ? ajaxCallBack : jsonCallBack;
    $.ajax({
        type: "GET",
        url: url,
        cache: false, 
        data: params,
        beforeSend: function(xhr) {
            xhr.setRequestHeader("Ajax", "true");
            xhr.setRequestHeader("UseAjaxError", "true");
        },
        complete: function() {
        },
        success: s,
        timeout: _ajaxTimeOut,
        dataType: "json",
        error: e
    });
}

不会触发getJSON方法的匿名函数回调.同样,对$.ajax的调用返回未找到的404.谁能看到我在做什么错？

解决方法:

如果您为其调用的URL没有分配响应,则Sinon fakeserver返回404.

看来您的问题是您正在调用的url与responseWith()参数中的URL不完全相同.此外,虽然不确定,但Sinon中的URL长度可能有限制.

标签：ajax,jasmine,sinon,javascript
来源： https://codeday.me/bug/20191101/1985350.html