编程语言
首页 > 编程语言> > java-在do-while循环中更新计时器上的JButton

java-在do-while循环中更新计时器上的JButton

作者:互联网

我在执行do-while循环时无法使JButton重复更新(与计时器一起使用)时遇到麻烦.我正在开发一个简单的游戏,在10 * 10的图块对象网格上玩,该对象对应于具有100个按钮的JButton arrayList.

程序的这一部分处理简单的寻路(即,如果我单击角色,然后单击一个空图块,则角色将在到达目标的途中在每个图块中移动).每个步骤之间都有一定的延迟,因此用户可以看到角色的进度.

在当前状态下,移动是正确的,但是JButton仅在角色到达目的地时更新,而不是在中间步骤上更新.

public void move(int terrainTile)
{
    int currentPosition = actorList.get(selectedActor).getPosition();
    int movementValue = 0;
    int destination = terrainTile;
    int destinationX = destination / 10;
    int destinationY = destination % 10;

    do
    {
        currentPosition = actorList.get(selectedActor).getPosition();  // Gets PC's current position (before move)
        System.out.println("Old position is " + currentPosition);
        int currentX = currentPosition / 10;
        int currentY = currentPosition % 10;


        if(actorList.get(selectedActor).getCurrentAP() > 0)
        {
            movementValue = 0;

            if(destinationX > currentX)
            {
                movementValue += 10;
            }

            if(destinationX < currentX)
            {
                movementValue -= 10;
            }

            if(destinationY > currentY)
            {
                movementValue += 1;
            }

            if(destinationY < currentY)
            {
                movementValue -= 1;
            }

            int nextStep = currentPosition + movementValue;

            myGame.setActorIdInTile(currentPosition, -1);  //Changes ActorId in PC current tile back to -1
            scrubTiles(currentPosition);

            actorList.get(selectedActor).setPosition(nextStep);  //  Sets new position in actor object
            System.out.println("Actor " + selectedActor + " " + actorList.get(selectedActor).getName() + " position has been updated to " + nextStep);

            myGame.setActorIdInTile(nextStep, selectedActor); // Sets ActorId in moved to Tile
            System.out.println("Tile " + nextStep + " actorId has been updated to " + selectedActor);

            buttons.get(nextStep).setIcon(new ImageIcon(actorList.get(selectedActor).getImageName()));

            // If orthagonal move AP-4
            if(movementValue == 10 || movementValue == -10 || movementValue == 1 || movementValue == -1)
            {
                actorList.get(selectedActor).reduceAP(4);
            }
            // If diagonal move AP-6
            else
            {
                actorList.get(selectedActor).reduceAP(6);
            }

            System.out.println(actorList.get(selectedActor).getName() + " has " + actorList.get(selectedActor).getCurrentAP() + " AP remaining");

            try
            {
                Thread.sleep(500);    // one second
            }
            catch (Exception e){} 

            buttons.get(nextStep).repaint();

        }

        else
        {
            System.out.println(actorList.get(selectedActor).getName() + " has insufficient AP to move");
            break;
        }

    }while(destination != (currentPosition + movementValue));

我尝试过的

> button.get(nextStep).repaint(); (尝试在设置imageIcon之后输入命令以重新绘制按钮.没有更改.
> button.get(nextStep).revalidate(); (没有100%的把握这是怎么做的-它是一种潜在的解决方案,但没有用.
>步骤1和2合并
>调查了摆动计时器类-每次触发actionEvent时都不会发生移动(仅当选择了角色且目标图块为空时),因此不确定如何使它起作用

任何帮助将不胜感激!

解决方法:

我确实不知道您想在评论中确切知道什么,尽管以上答案的1对我来说似乎是真正的原因.看一下这个示例程序,只需将您的调用添加到timerAction内部的move(…)方法中,似乎可以为您工作.在这里试试这段代码:

import java.awt.*;
import java.awt.event.*;
import javax.swing.*;

public class GridExample
{
    private static final int SIZE = 36;
    private JButton[] buttons;
    private int presentPos;
    private int desiredPos;
    private Timer timer;
    private Icon infoIcon = 
                UIManager.getIcon("OptionPane.informationIcon");

    private ActionListener timerAction = new ActionListener()
    {
        public void actionPerformed(ActionEvent ae)
        {
            buttons[presentPos].setIcon(null);
            if (desiredPos < presentPos)
            {
                presentPos--;
                buttons[presentPos].setIcon(infoIcon);
            }
            else if (desiredPos > presentPos)
            {
                presentPos++;
                buttons[presentPos].setIcon(infoIcon);
            }
            else if (desiredPos == presentPos)
            {
                timer.stop();
                buttons[presentPos].setIcon(infoIcon);
            }
        }
    };

    public GridExample()
    {
        buttons = new JButton[SIZE];
        presentPos = 0;
        desiredPos = 0;
    }

    private void createAndDisplayGUI()
    {
        JFrame frame = new JFrame("Grid Game");
        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

        JPanel contentPane = new JPanel();
        contentPane.setLayout(new GridLayout(6, 6, 5, 5));
        for (int i = 0; i < SIZE; i++)
        {
            final int counter = i;
            buttons[i] = new JButton();
            buttons[i].setActionCommand("" + i);
            buttons[i].addActionListener(new ActionListener()
            {
                public void actionPerformed(ActionEvent ae)
                {
                    desiredPos = Integer.parseInt(
                                    (String) buttons[counter].getActionCommand());
                    timer.start();              
                }
            });
            contentPane.add(buttons[i]);
        }
        buttons[presentPos].setIcon(infoIcon);

        frame.setContentPane(contentPane);
        frame.pack();
        frame.setLocationByPlatform(true);
        frame.setVisible(true);
        timer = new Timer(1000, timerAction);
    }

    public static void main(String... args)
    {
        SwingUtilities.invokeLater(new Runnable()
        {
            public void run()
            {
                new GridExample().createAndDisplayGUI();
            }
        });
    }
}

标签:imageicon,timer,java
来源: https://codeday.me/bug/20191101/1982312.html