Java Comparator reversed()方法产生了奇怪的结果
作者:互联网
我有一个关于分数背包问题的编程作业.作为解决问题的方法,我们需要按利润/重量比的降序填充项目.我使用自定义比较器对项目进行排序.
检查以下Item类中的profitByWeightComparator:
class Item {
private int itemNumber;
private int profit;
private int weight;
public Item() {
profit=weight=0;
}
public Item(int itemNumber, int profit, int weight) {
this.itemNumber = itemNumber;
this.profit = profit;
this.weight = weight;
}
public String toString() {
return "("+this.getItemNumber()+", "+this.getProfit()+", "+this.getWeight()+")";
}
public static Comparator<Item> profitByWeightComparator = new Comparator<Item>() {
@Override
public int compare(Item item1, Item item2) {
double item1Ratio = (double)(item1.getProfit()/item1.getWeight());
double item2Ratio = (double)(item2.getProfit()/item2.getWeight());
return new Double(item1Ratio).compareTo(new Double(item2Ratio));
}
};
public int getItemNumber() {
return this.itemNumber;
}
public int getProfit() {
return this.profit;
}
public int getWeight() {
return this.weight;
}
}
我使用Comparator类的reversed()方法以降序排序.
检查下面的KnapSack类中的fillGreedyByProfitPerWeight()方法:
class KnapSack {
Item [] items;
int capacity;
KnapSack() {
Scanner sc = new Scanner(System.in);
System.out.println("Enter number of items: ");
int n = sc.nextInt();
items = new Item[n];
System.out.println("Enter the capacity of the KnapSack: ");
this.capacity = sc.nextInt();
int profit = 0;
int weight = 0;
for(int i = 0; i < n; i++) {
System.out.println("Enter Item "+(i+1)+" (Format - Profit<Space>Weight):");
profit = sc.nextInt();
weight = sc.nextInt();
items[i] = new Item((i+1), profit, weight);
}
fillGreedyByProfitPerWeight();
}
public void fillGreedyByProfitPerWeight() {
Arrays.sort(items,Item.profitByWeightComparator.reversed());
fillKnapSack("Greedy by Profit Per Weight");
}
public void fillKnapSack(String strategy) {
double totalProfit = 0d;
int currItemProfit = 0, currItemWeight = 0, i=0, tempCapacity = capacity;
ArrayList<Integer> filledItems = new ArrayList<Integer>();
System.out.println(Arrays.toString(items));
for(i = 0; i < items.length; i++) {
currItemProfit = items[i].getProfit();
currItemWeight = items[i].getWeight();
if(currItemWeight <= tempCapacity) {
filledItems.add(items[i].getItemNumber());
totalProfit += currItemProfit;
tempCapacity -= currItemWeight;
}
else {
break;
}
}
double fraction = (double)tempCapacity/currItemWeight;
totalProfit += (double)(currItemProfit*fraction);
System.out.println("KnapSack filled using strategy: "+strategy+".\nMaximum Profit: "+totalProfit);
System.out.print("Items added: ");
for(int k:filledItems) {
System.out.print(k+" ");
}
if(fraction != 0d)
System.out.print("and "+tempCapacity+"/"+currItemWeight+" of "+items[i].getItemNumber());
System.out.println("\n");
}
public static void main(String[] args) {
KnapSack obj = new KnapSack();
}
}
但是,在某些情况下,这会导致奇怪的结果.例如当我尝试以下输入时:
No. of Items: 5
Capacity: 20
Item 1 (Format - Profit<space>Weight): 20 1
Item 2 (Format - Profit<space>Weight): 10 1
Item 3 (Format - Profit<space>Weight): 10 2
Item 4 (Format - Profit<space>Weight): 40 8
Item 5 (Format - Profit<space>Weight): 60 11
最大利润的预期输出为125(项目1,项目2,项目5,项目3和项目4的5/8),但是获得的输出如下:
(请检查链接,因为我还不能嵌入图像)
请注意,排序顺序被弄乱了,因为第5项不应排在倒序的排序顺序的最后,它必须是第3位.这里的罪魁祸首是什么?
解决方法:
您的比较器执行除法不正确:首先将int转换为double然后除法,然后先除法,然后将结果转换为double.到那时该分数已消失,因此结果无法正确排序.
更改比较器,如下所示:
public static Comparator<Item> profitByWeightComparator = new Comparator<Item>() {
@Override
public int compare(Item item1, Item item2) {
double item1Ratio = ((double)item1.getProfit())/item1.getWeight();
double item2Ratio = ((double)(item2.getProfit())/item2.getWeight();
return Double.compare(item1Ratio, item2Ratio);
}
};
现在,除法以双精度完成,并且比较不截断小数部分.
如果权重严格为正,并且利润*权重没有溢出整数,则可以完全跳过除法,比较比率,如下所示:
public static Comparator<Item> profitByWeightComparator = new Comparator<Item>() {
@Override
public int compare(Item item1, Item item2) {
return Integer.compare(
item1.getProfit() * item2.getWeight()
, item2.getProfit() * item1.getWeight()
);
}
};
标签:knapsack-problem,comparator,java,sorting 来源: https://codeday.me/bug/20191025/1930660.html