关于java的QuickHit打字游戏小项目
作者:互联网
public class Player {
Scanner input = new Scanner(System.in);
//玩家属性
private int level = 0;//等级
private int curScore = 0;//积分
private long stratTime = 0;//开始时间
private int elapsdTime = 0;//所用时间
//封装
public int getLevel() {
return level;
}
public void setLevel(int level) {
this.level = level;
}
public int getCurScore() {
return curScore;
}
public void setCurScore(int curScore) {
this.curScore = curScore;
}
public long getStartTime() {
return stratTime;
}
public void setStartTime(int strTime) {
this.stratTime = strTime;
}
public int getElapsdTime() {
return elapsdTime;
}
public void setElapsdTime(int elapsdTime) {
this.elapsdTime = elapsdTime;
}
//封装
Game game = new Game(this);//创建游戏对象,并装入玩家
public void play ()throws Exception//玩游戏
{
for (int i = 0; i <LevelParam.levels.length; i++) {//游玩次数
//一次通关
Level level = LevelParam.levels[this.level];
this.stratTime = System.currentTimeMillis();
for (int j = 1; j <= level.getStrTime(); j++) {
System.out.println("第" + j + "次");
String out = game.pringStr();//接收字符串
String in = input.next();//接收玩家输入的字符串
game.printResult(out, in);//比较并打印结果
}
this.curScore += level.getPerSore();
System.out.println("通过第" + (this.level + 1) + "关,积分:" + curScore);
this.level++;//等级增加
//一次通关
}
}
}
public class Game {
private Player player;//玩家
public Game(){}//构造
public Game(Player player){this.player=player;}//构造
String pringStr()//输出字符串方法
{
Level level = LevelParam.levels[this.player.getLevel()];
Random random = new Random();
StringBuffer sb=new StringBuffer();
for (int i = 0; i < level.getStrLength(); i++) {
int rand = random.nextInt(6);
switch(rand)
{
case 0:
sb.append("a");
break;
case 1:
sb.append("b");
break;
case 2:
sb.append("c");
break;
case 3:
sb.append("d");
break;
case 4:
sb.append("e");
break;
case 5:
sb.append("f");
break;
}
}
System.out.println(sb.toString());
return sb.toString();
}
public void printResult(String out,String in)//比较结果
{
if(out.equals(in))
{
System.out.println("输入成功");
long endtime=System.currentTimeMillis();
double timecha=(endtime-this.player.getStartTime())*1.0/1000;
if(timecha>(LevelParam.levels[this.player.getLevel()].getTimeLimit()))
{
System.out.println("输入超时游戏结束");
System.exit(0);
}
}
else{
System.out.println("输入失败,退出游戏");
System.exit(0);
}
}
}
public class Level {
public int getLevelON() {
return levelON;
}
public void setLevelON(int levelON) {
this.levelON = levelON;
}
public int getStrLength() {
return strLength;
}
public void setStrLength(int strLength) {
this.strLength = strLength;
}
public int getStrTime() {
return strTime;
}
public void setStrTime(int strTime) {
this.strTime = strTime;
}
public int getTimeLimit() {
return timeLimit;
}
public void setTimeLimit(int timeLimit) {
this.timeLimit = timeLimit;
}
public int getPerSore() {
return perSore;
}
public void setPerSore(int perSore) {
this.perSore = perSore;
}
private int levelON=0;//等级
private int strLength=0;//字符串长度
private int strTime=0;//输入次数
private int timeLimit=0;//时间限制
private int perSore=0;//该等级得分
//构造
public Level(){}
public Level(int levelON, int strLength, int strTime, int timeLimit, int perSore) {
this.levelON = levelON;
this.strLength = strLength;
this.strTime = strTime;
this.timeLimit = timeLimit;
this.perSore = perSore;
}
//构造
}
public class LevelParam {
public static final Level levels[]=new Level[6];//常量数组属性
static{//设置并初始化等级难度
//等级,输入字数,输入次数,时间限制,得分
levels[0]=new Level(1,2,2,30,1);
levels[1]=new Level(1,3,2,30,2);
levels[2]=new Level(1,4,2,30,3);
levels[3]=new Level(1,5,2,30,4);
levels[4]=new Level(1,6,2,30,5);
levels[5]=new Level(1,7,2,30,6);
}
}
这个项目中,切实体会的是项目的面向对象设计,以及编程思想的重要。
其中使用构造以及static来初始化参数和传参,对于初学的我来说
的确是很巧妙的运用方法,
在我试图使用C++来写这个程序的时候,也切实体会到了编程语言上的实际差异
很多东西使用c++实现起来没有java方便,当然主要是我的理解还不够以及
对于C++的编程思路和技巧掌握不到位,以至于我现在还没有完成。我会尽量
完成它以提高自己的理解。
标签:QuickHit,java,Level,int,void,level,打字,System,public 来源: https://www.cnblogs.com/deemohans/p/11706938.html