无法使用Python遍历分页的API响应
作者:互联网
所以,我正在抓这个.使用HubSpot的API,我需要获取客户的“门户”(帐户)中所有公司的列表.可悲的是,标准API调用一次仅返回100家公司.当它确实返回响应时,它包含两个参数,这些参数使通过响应进行分页成为可能.
其中之一是“具有更多”:True(这使您知道是否可以再看到更多页面),另一个是“ offset”:12345678(将请求偏移的时间戳.)
您可以将这两个参数传递回下一个API调用以获取下一页.因此,例如,最初的API调用可能类似于:
"https://api.hubapi.com/companies/v2/companies/?hapikey={hapikey}".format(hapikey=wta_hubspot_api_key)
而后续致电可能如下:
"https://api.hubapi.com/companies/v2/companies/?hapikey={hapikey}&offset={offset}".format(hapikey=wta_hubspot_api_key, offset=offset)
因此,这是我到目前为止尝试过的:
#!/usr/bin/python
# -*- coding: utf-8 -*-
import sys
import os.path
import requests
import json
import csv
import glob2
import shutil
import time
import time as howLong
from time import sleep
from time import gmtime, strftime
HubSpot_Customer_Portal_ID = "XXXXXX"
wta_hubspot_api_key = "XXXXXXXX-XXXX-XXXX-XXXX-XXXXXXXXXXXX"
findCSV = glob2.glob('*contact*.csv')
theDate = time=strftime("%Y-%m-%d", gmtime())
theTime = time=strftime("%H:%M:%S", gmtime())
try:
testData = findCSV[0]
except IndexError:
print ("\nSyncronisation attempted on {date} at {time}: There are no \"contact\" CSVs, please upload one and try again.\n").format(date=theDate, time=theTime)
print("====================================================================================================================\n")
sys.exit()
for theCSV in findCSV:
def get_companies():
create_get_recent_companies_call = "https://api.hubapi.com/companies/v2/companies/?hapikey={hapikey}".format(hapikey=wta_hubspot_api_key)
headers = {'content-type': 'application/json'}
create_get_recent_companies_response = requests.get(create_get_recent_companies_call, headers=headers)
if create_get_recent_companies_response.status_code == 200:
offset = create_get_recent_companies_response.json()[u'offset']
hasMore = create_get_recent_companies_response.json()[u'has-more']
while hasMore == True:
for i in create_get_recent_companies_response.json()[u'companies']:
get_more_companies_call = "https://api.hubapi.com/companies/v2/companies/?hapikey={hapikey}&offset={offset}".format(hapikey=wta_hubspot_api_key, offset=offset)
get_more_companies_call_response = requests.get(get_more_companies_call, headers=headers)
companyName = i[u'properties'][u'name'][u'value']
print("{companyName}".format(companyName=companyName))
else:
print("Something went wrong, check the supplied field values.\n")
print(json.dumps(create_get_recent_companies_response.json(), sort_keys=True, indent=4))
if __name__ == "__main__":
get_companies()
sys.exit()
问题在于,它只会不断返回最初的100个结果.发生这种情况是因为参数“ has-more”:True在初始调用时为true,因此它将继续返回相同的值…
我的理想情况是,我能够解析大约120个响应页面中的所有公司(大约有12000个公司).当我浏览每个页面时,我想将其JSON内容追加到列表中,以便最终获得包含所有120个页面的JSON响应的列表,以便我可以解析该列表以用于其他功能.
我迫切需要一个解决方案:(
这是我要在主脚本中替换的功能:
def get_companies():
create_get_recent_companies_call = "https://api.hubapi.com/companies/v2/companies/recent/modified?hapikey={hapikey}".format(hapikey=wta_hubspot_api_key)
headers = {'content-type': 'application/json'}
create_get_recent_companies_response = requests.get(create_get_recent_companies_call, headers=headers)
if create_get_recent_companies_response.status_code == 200:
for i in create_get_recent_companies_response.json()[u'results']:
company_name = i[u'properties'][u'name'][u'value']
#print(company_name)
if row[0].lower() == str(company_name).lower():
contact_company_id = i[u'companyId']
#print(contact_company_id)
return contact_company_id
else:
print("Something went wrong, check the supplied field values.\n")
#print(json.dumps(create_get_recent_companies_response.json(), sort_keys=True, indent=4))
解决方法:
问题似乎是:
>您在第一个电话中获得了补偿,但对此电话返回的实际公司数据不做任何事情.
>然后在while循环中使用相同的偏移量;您永远不会在后续通话中使用新的.这就是为什么您每次都会得到相同的公司的原因.
我认为get_companies()的这段代码应该对您有用.显然,我无法测试它,但是希望可以:
def get_companies():
create_get_recent_companies_call = "https://api.hubapi.com/companies/v2/companies/?hapikey={hapikey}".format(hapikey=wta_hubspot_api_key)
headers = {'content-type': 'application/json'}
create_get_recent_companies_response = requests.get(create_get_recent_companies_call, headers=headers)
if create_get_recent_companies_response.status_code == 200:
while True:
for i in create_get_recent_companies_response.json()[u'companies']:
companyName = i[u'properties'][u'name'][u'value']
print("{companyName}".format(companyName=companyName))
offset = create_get_recent_companies_response.json()[u'offset']
hasMore = create_get_recent_companies_response.json()[u'has-more']
if not hasMore:
break
else:
create_get_recent_companies_call = "https://api.hubapi.com/companies/v2/companies/?hapikey={hapikey}&offset={offset}".format(hapikey=wta_hubspot_api_key, offset=offset)
create_get_recent_companies_response = requests.get(create_get_recent_companies_call, headers=headers)
else:
print("Something went wrong, check the supplied field values.\n")
print(json.dumps(create_get_recent_companies_response.json(), sort_keys=True, indent=4))
严格来说,不需要休息后的else,但与Zen of Python“显式要好于隐式”保持一致
请注意,您只需要检查一次200响应代码,如果循环中出现问题,您将错过它.您可能应该将所有调用放入循环中,并每次都检查是否有正确的响应.
标签:python,json,python-2-7,loops,hubspot 来源: https://codeday.me/bug/20191009/1881017.html