c# – Unity在Play上崩溃,很可能是无限循环,但找不到问题
作者:互联网
谢谢阅读.
我目前正在使用C#在Unity中构建一个小型存储卡游戏.我已经完成了代码的主要部分但是当我按某个场景上的播放按钮时,Unity会冻结.
我相信这是由于一个无限的While循环,但我找不到问题.我真的很感激任何人都可以提供帮助.我将在下面留下我的代码.提前致谢.
using System.Collections;
using System.Collections.Generic;
using UnityEngine.UI;
using UnityEngine.SceneManagement;
using UnityEngine;
public class Pairs : MonoBehaviour {
public Sprite[] face; //array of card faces
public Sprite back;
public GameObject[] deck; //array of deck
public Text pairsCount;
private bool deckSetUp = false;
private int pairsLeft = 13;
// Update is called once per frame
void Update () {
if (!deckSetUp)
{
SetUpDeck();
}
if (Input.GetMouseButtonUp(0)) //detects left click
{
CheckDeck();
}
}//Update
void SetUpDeck()
{
for (int ix = 0; ix < 2; ix++)
{
for(int i = 1; i < 14; i++)//sets up card value (2-10 JQKA)
{
bool test = false;
int val = 0;
while (!test)
{
val = Random.Range(0, deck.Length);
test = !(deck[val].GetComponent<Card>().SetUp);
}//while
//sets up cards
deck[val].GetComponent<Card>().Number = i;
deck[val].GetComponent<Card>().SetUp = true;
}//nested for
}//for
foreach (GameObject crd in deck)
{
crd.GetComponent<Card>().setUpArt();
}
if (!deckSetUp)
{
deckSetUp = true;
}
}//SetUpDeck
public Sprite getBack()
{
return back;
}//getBack
public Sprite getFace(int i)
{
return face[i - 1];
}//getFace
void CheckDeck()
{
List < int > crd = new List<int>();
for(int i = 0; i < deck.Length; i++)
{
if(deck[i].GetComponent<Card>().State == 1)
{
crd.Add(i);
}
}
if(crd.Count == 2)
{
CompareCards(crd);
}
}//CheckDeck
void CompareCards(List<int> crd)
{
Card.NO_TURN = true; //stops cards turning
int x = 0;
if(deck[crd[0]].GetComponent<Card>().Number ==
deck[crd[1]].GetComponent<Card>().Number)
{
x = 2;
pairsLeft--;
pairsCount.text = "PAIRS REMAINING: " + pairsLeft;
if(pairsLeft == 0) // goes to home screen when game has been won
{
SceneManager.LoadScene("Home");
}
}
for(int j = 0; j < crd.Count; j++)
{
deck[crd[j]].GetComponent<Card>().State = x;
deck[crd[j]].GetComponent<Card>().PairCheck();
}
}//CompareCards
}
我相信问题在于while(!test),但我不知道为什么测试永远不会成真.
using System.Collections;
using System.Collections.Generic;
using UnityEngine.UI;
using UnityEngine;
public class Card : MonoBehaviour {
public static bool NO_TURN = false;
[SerializeField]
private int cardState; //state of card
[SerializeField]
private int cardNumber; //Card value (1-13)
[SerializeField]
private bool _setUp = false;
private Sprite back; //card back (Green square)
private Sprite face; //card face (1-10 JQKA)
private GameObject pairsManager;
void Begin()
{
cardState = 1; //cards face down
pairsManager = GameObject.FindGameObjectWithTag("PairsManager");
}
public void setUpArt()
{
back = pairsManager.GetComponent<Pairs>().getBack();
face = pairsManager.GetComponent<Pairs>().getFace(cardNumber);
turnCard();//turns the card
}
public void turnCard() //handles turning of card
{
if (cardState == 0)
{
cardState = 1;
}
else if(cardState == 1)
{
cardState = 0;
}
if (cardState == 0 && !NO_TURN)
{
GetComponent<Image>().sprite = back; // shows card back
}
else if (cardState == 1 && !NO_TURN)
{
GetComponent<Image>().sprite = face; // shows card front
}
}
//setters and getters
public int Number
{
get {return cardNumber;}
set { cardNumber = value;}
}
public int State
{
get { return cardState; }
set { cardState = value; }
}
public bool SetUp
{
get { return _setUp; }
set { _setUp = value; }
}
public void PairCheck()
{
StartCoroutine(pause ());
}
IEnumerator pause()
{
yield return new WaitForSeconds(1);
if (cardState == 0)
{
GetComponent<Image>().sprite = back;
}
else if (cardState == 1)
{
GetComponent<Image>().sprite = face;
}
}
}
感谢您的阅读,如果有帮助,我会发布一个指向github存储库的链接.
github repository
解决方法:
您的deck数组中至少有一张卡,其中_setUp设置为true,这将使其进入无限循环.
它进入无限循环的原因是因为它将所有可用的_setUp设置为true,并且它将继续寻找设置为false的_setUp并且它永远不会找到任何.
你需要至少26个具有_setUp为false的对象的原因是因为在嵌套的for循环中你循环13次然后你做了两次,总共有26个循环.所以你需要至少26个对象.
你可以做些什么来确保它们都是假的是在进入for循环之前将它们全部设置为false
for(int i = 0; i < deck.Length; i++)
{
deck[i].GetComponent<Card>().SetUp = false;
}
标签:android,unity3d,visual-studio-2017,c-2 来源: https://codeday.me/bug/20191007/1866735.html