python – 装饰类以监视属性更改
作者:互联网
我想让课程在其中一个属性发生变化时自动向订阅者发送通知.所以,如果我写这个代码:
@ChangeMonitor
class ChangingClass(object):
def __init__(self, x):
self.x = x
changer = ChangingClass(5)
print("Going to change x.")
changer.x = 6
print("Going to not change x.")
changer.x = 6
print("End of program")
输出将是:
Going to change x
Old x = 5, new x = 6
Going to not change x.
End of program.
我的问题是如何实现ChangeMonitor装饰器类.在上面的示例中,我假设它将打印一行指示属性的更改,但出于有用的目的,它可以向订阅的对象发送通知.
解决方法:
你必须添加一个__setattr__()
method:
def ChangeMonitor(cls):
_sentinel = object()
old_setattr = getattr(cls, '__setattr__', None)
def __setattr__(self, name, value):
old = getattr(self, name, _sentinel)
if old not is _sentinel and old != value:
print "Old {0} = {1!r}, new {0} = {2!r}".format(name, old, value)
if old_setattr:
old_setattr(self, name, value)
else:
# Old-style class
self.__dict__[name] = value
cls.__setattr__ = __setattr__
return cls
这应该处理现有的__setattr__钩子. _sentinel用于允许None作为旧值.
演示:
>>> changer = ChangingClass(5)
>>> changer.x = 6
Old x = 5, new x = 6
>>> changer.x = 6
>>> # nothing printed
...
>>> changer.x = None
Old x = 6, new x = None
>>> changer.x = 6
Old x = None, new x = 6
标签:python-decorators,python,decorator 来源: https://codeday.me/bug/20191005/1856165.html