javascript – 使用react-hooks在更新状态时执行异步代码
作者:互联网
我有类似的东西:
const [loading, setLoading] = useState(false);
...
setLoading(true);
doSomething(); // <--- when here, loading is still false.
设置状态仍然是异步的,那么等待此setLoading()调用完成的最佳方法是什么?
setLoading()似乎不接受像setState()那样的回调.
一个例子
基于类的
getNextPage = () => {
// This will scroll back to the top, and also trigger the prefetch for the next page on the way up.
goToTop();
if (this.state.pagesSeen.includes(this.state.page + 1)) {
return this.setState({
page: this.state.page + 1,
});
}
if (this.state.prefetchedOrders) {
const allOrders = this.state.orders.concat(this.state.prefetchedOrders);
return this.setState({
orders: allOrders,
page: this.state.page + 1,
pagesSeen: [...this.state.pagesSeen, this.state.page + 1],
prefetchedOrders: null,
});
}
this.setState(
{
isLoading: true,
},
() => {
getOrders({
page: this.state.page + 1,
query: this.state.query,
held: this.state.holdMode,
statuses: filterMap[this.state.filterBy],
})
.then((o) => {
const { orders } = o.data;
const allOrders = this.state.orders.concat(orders);
this.setState({
orders: allOrders,
isLoading: false,
page: this.state.page + 1,
pagesSeen: [...this.state.pagesSeen, this.state.page + 1],
// Just in case we're in the middle of a prefetch.
prefetchedOrders: null,
});
})
.catch(e => console.error(e.message));
},
);
};
转换为基于功能
const getNextPage = () => {
// This will scroll back to the top, and also trigger the prefetch for the next page on the way up.
goToTop();
if (pagesSeen.includes(page + 1)) {
return setPage(page + 1);
}
if (prefetchedOrders) {
const allOrders = orders.concat(prefetchedOrders);
setOrders(allOrders);
setPage(page + 1);
setPagesSeen([...pagesSeen, page + 1]);
setPrefetchedOrders(null);
return;
}
setIsLoading(true);
getOrders({
page: page + 1,
query: localQuery,
held: localHoldMode,
statuses: filterMap[filterBy],
})
.then((o) => {
const { orders: fetchedOrders } = o.data;
const allOrders = orders.concat(fetchedOrders);
setOrders(allOrders);
setPage(page + 1);
setPagesSeen([...pagesSeen, page + 1]);
setPrefetchedOrders(null);
setIsLoading(false);
})
.catch(e => console.error(e.message));
};
在上面,我们希望按顺序运行每个setWhatever调用.这是否意味着我们需要设置许多不同的useEffect钩子来复制这种行为?
解决方法:
在状态更新完成之后,useState setter不提供回调,就像setState在React类组件中那样.为了复制相同的行为,您可以在React类组件中使用类似的模式,如componentDidUpdate生命周期方法,使用钩子使用useEffect
useEffect hooks将第二个参数作为一个值数组,React需要在渲染周期完成后监视更改.
const [loading, setLoading] = useState(false);
...
useEffect(() => {
doSomething(); // This is be executed when `loading` state changes
}, [loading])
setLoading(true);
编辑
与setState不同,useState钩子的更新程序没有回调,但您始终可以使用useEffect来复制上述行为.但是,您需要确定负载变化
代码的功能方法看起来像
function usePrevious(value) {
const ref = useRef();
useEffect(() => {
ref.current = value;
});
return ref.current;
}
const prevLoading = usePrevious(isLoading);
useEffect(() => {
if (!prevLoading && isLoading) {
getOrders({
page: page + 1,
query: localQuery,
held: localHoldMode,
statuses: filterMap[filterBy],
})
.then((o) => {
const { orders: fetchedOrders } = o.data;
const allOrders = orders.concat(fetchedOrders);
setOrders(allOrders);
setPage(page + 1);
setPagesSeen([...pagesSeen, page + 1]);
setPrefetchedOrders(null);
setIsLoading(false);
})
.catch(e => console.error(e.message));
}
}, [isLoading, preFetchedOrders, orders, page, pagesSeen]);
const getNextPage = () => {
// This will scroll back to the top, and also trigger the prefetch for the next page on the way up.
goToTop();
if (pagesSeen.includes(page + 1)) {
return setPage(page + 1);
}
if (prefetchedOrders) {
const allOrders = orders.concat(prefetchedOrders);
setOrders(allOrders);
setPage(page + 1);
setPagesSeen([...pagesSeen, page + 1]);
setPrefetchedOrders(null);
return;
}
setIsLoading(true);
};
标签:javascript,reactjs,callback,react-hooks 来源: https://codeday.me/bug/20191005/1854888.html