服务器和客户端之间的实时视频流 – 使用Java
作者:互联网
这是我正在进行的项目的一部分.我有两个桌面java应用程序,一个在服务器上运行(有真正的IP),另一个是客户端.我只想从连接到服务器应用程序的网络摄像头流式传输实时视频,并在客户端应用程序上播放.我想从多个摄像头进行流式传输.
我一直在寻找Xuggler,JMF,Red5,VLCj之间的日子.我无法想象我应该从哪里开始,因为我刚接触编程中的媒体.
我应该从哪里开始的想法?
提前致谢
解决方法:
我建议您使用VLCJ,因为除了实时视频流之外,您还可以使用VLC媒体播放器的所有功能.此外,它适用于Linux,Windows和Mac.如果您可以使用VLC直播您的网络摄像头,那么您可以使用VLCJ进行相同操作.
有关如何使用它的详细信息,请参阅VLCJ wiki page.他们在维基中提供了很多例子.以下是使用VLCJ的Http Streaming示例.复制自VLCJ示例.
/*
* This file is part of VLCJ.
*
* VLCJ is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation, either version 3 of the License, or
* (at your option) any later version.
*
* VLCJ is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with VLCJ. If not, see <http://www.gnu.org/licenses/>.
*
* Copyright 2009, 2010, 2011 Caprica Software Limited.
*/
package uk.co.caprica.vlcj.test.streaming;
import uk.co.caprica.vlcj.player.MediaPlayerFactory;
import uk.co.caprica.vlcj.player.headless.HeadlessMediaPlayer;
import uk.co.caprica.vlcj.test.VlcjTest;
/**
* An example of how to stream a media file over HTTP.
* <p>
* The client specifies an MRL of <code>http://127.0.0.1:5555</code>
*/
public class StreamHttp extends VlcjTest {
public static void main(String[] args) throws Exception {
if(args.length != 1) {
System.out.println("Specify a single MRL to stream");
System.exit(1);
}
String media = args[0];
String options = formatHttpStream("127.0.0.1", 5555);
System.out.println("Streaming '" + media + "' to '" + options + "'");
MediaPlayerFactory mediaPlayerFactory = new MediaPlayerFactory(args);
HeadlessMediaPlayer mediaPlayer = mediaPlayerFactory.newHeadlessMediaPlayer();
mediaPlayer.playMedia(media, options);
// Don't exit
Thread.currentThread().join();
}
private static String formatHttpStream(String serverAddress, int serverPort) {
StringBuilder sb = new StringBuilder(60);
sb.append(":sout=#duplicate{dst=std{access=http,mux=ts,");
sb.append("dst=");
sb.append(serverAddress);
sb.append(':');
sb.append(serverPort);
sb.append("}}");
return sb.toString();
}
}
标签:java,video-streaming,client-server 来源: https://codeday.me/bug/20191004/1851683.html