java – 在JApplet中按顺序播放音频片段
作者:互联网
我正在尝试按顺序播放音频片段,但它们都在同一时间播放.我不确定我做错了什么.能否请你帮忙.我正在使用JFrame,这段代码给出了运行时错误.
AudioClip click;
AudioClip click2;
URL urlClick1 = DisplayMath.class.getResource("number11.wav");
click = Applet.newAudioClip(urlClick1);
URL urlClick2 = DisplayMath.class.getResource("number12.wav");
click2 = Applet.newAudioClip(urlClick2);
click.play();
click.notify();
try {
click2.wait();
}
catch (InterruptedException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
click2.play();
解决方法:
使用AudioClip无法实现您想要实现的功能,但是它是否附加了LineListener的Clip.请参阅此示例,该示例在两个剪辑之间翻转.
import javax.sound.sampled.LineListener;
import javax.swing.*;
class TwoClips {
public static void main(String[] args) throws Exception {
URL url1 = new URL("http://pscode.org/media/100_2817-linear.wav");
URL url2 = new URL("http://pscode.org/media/leftright.wav");
final Clip clip1 = AudioSystem.getClip();
clip1.open(AudioSystem.getAudioInputStream(url1));
final Clip clip2 = AudioSystem.getClip();
clip2.open(AudioSystem.getAudioInputStream(url2));
LineListener listener = new LineListener() {
Clip currentClip = clip1;
@Override
public void update(LineEvent event) {
if (event.getType() == LineEvent.Type.STOP) {
if (currentClip == clip1) {
currentClip = clip2;
} else {
currentClip = clip1;
}
currentClip.setFramePosition(0);
currentClip.start();
}
}
};
clip1.addLineListener(listener);
clip2.addLineListener(listener);
Runnable r = new Runnable() {
@Override
public void run() {
clip1.start();
JOptionPane.showMessageDialog(null, "Close me to exit!");
}
};
// Swing GUIs should be created and updated on the EDT
// http://docs.oracle.com/javase/tutorial/uiswing/concurrency/initial.html
SwingUtilities.invokeLater(r);
}
}
标签:javasound,japplet,clip,java,audio 来源: https://codeday.me/bug/20191002/1844877.html