java – 类构造函数中的stackoverflow错误

请原谅可能是一个非常基本的问题,但我正在编写一个程序来存储员工信息,它可以正常工作,直到它尝试在我的员工类中设置信息.它给出了stackoverflow错误,我无法弄清楚为什么.谢谢你的帮助.

主要课程：

import java.util.Scanner;

public class Main
{
    public static void main(String[] args)
    {
        Scanner Input = new Scanner(System.in);

        System.out.println("Enter the number of employees to enter.");
        int employeeCount = Input.nextInt();
        Input.nextLine();

        Employee employee[] = new Employee[employeeCount];
        String namesTemp;
        String streetTemp;
        String cityTemp;
        String stateTemp;
        String zipCodeTemp;
        String address;
        String dateOfHireTemp;

        for(int x = 0; x < employeeCount; x++)
        {
            System.out.println("Please enter the name of Employee " + (x + 1));
            namesTemp = Input.nextLine();
            System.out.println("Please enter the street for Employee " + (x + 1));
            streetTemp = Input.nextLine();
            System.out.println("Please enter the city of Employee " + (x + 1));
            cityTemp = Input.nextLine();
            System.out.println("Please enter the state of Employee " + (x + 1));
            stateTemp = Input.nextLine();
            System.out.println("Please enter the zip code of Employee " + (x + 1));
            zipCodeTemp = Input.nextLine();
            address = streetTemp + ", " + cityTemp + ", " + stateTemp + ", " + zipCodeTemp;
            System.out.println("Please enter the date of hire for Employee " + (x + 1));
            dateOfHireTemp = Input.nextLine();
            System.out.println("The employee ID for employee " + (x + 1) + " is " + (x + 1));
            employee[x] = new Employee(x, namesTemp, address, dateOfHireTemp);
        }
    }
}

员工类：

public class Employee
{
    private int employeeID;
    private Name name;
    private Address address;
    private DateOfHire hireDate;

    public Employee()
    {

    }

    public Employee(int employeeID, String name, String address, String hireDate)
    {
        String temp;
        Name employeeName = new Name(name);
        this.employeeID = employeeID;
    }
}

名字类：

public class Name 
{
    public Name name;

    public Name(String name)
    {
        Name employeeName = new Name(name);
        this.name = employeeName;
    }
}

解决方法:

StackoverflowExceptions最常见的原因是在不知不觉中有递归,这是发生在这里吗？ …

public Name(String name)
{
    Name employeeName = new Name(name);  // **** YIKES!! ***
    this.name = employeeName;
}

宾果游戏：递归！

此构造函数将创建一个新的Name对象,其构造函数将创建一个新的Name对象,其构造函数将… …因此您将无限制地创建新的Name对象,或者直到堆栈内存耗尽.解决方案：不要这样做.为String指定名称：

class Name {
    String name; // ***** String field!

    public Name(String name)
    {
        this.name = name;  // this.name is a String field
    }

标签：java,constructor,stack-overflow
来源： https://codeday.me/bug/20190918/1811377.html