如何让程序回到代码的顶部,而不是关闭

参见英文答案 > Asking the user for input until they give a valid response                                    18个
我试图弄清楚如何让Python回到代码的顶部.在SmallBasic中,你做到了

start:
    textwindow.writeline("Poo")
    goto start

但我无法弄清楚你是如何用Python做到的：/任何人的想法？

我试图循环的代码就是这个

#Alan's Toolkit for conversions

def start() :
    print ("Welcome to the converter toolkit made by Alan.")
    op = input ("Please input what operation you wish to perform. 1 for Fahrenheit to Celsius, 2 for meters to centimetres and 3 for megabytes to gigabytes")

if op == "1":
    f1 = input ("Please enter your fahrenheit temperature: ")
    f1 = int(f1)

    a1 = (f1 - 32) / 1.8
    a1 = str(a1)

    print (a1+" celsius") 

elif op == "2":
    m1 = input ("Please input your the amount of meters you wish to convert: ")
    m1 = int(m1)
    m2 = (m1 * 100)

    m2 = str(m2)
    print (m2+" m")


if op == "3":
    mb1 = input ("Please input the amount of megabytes you want to convert")
    mb1 = int(mb1)
    mb2 = (mb1 / 1024)
    mb3 = (mb2 / 1024)

    mb3 = str(mb3)

    print (mb3+" GB")

else:
    print ("Sorry, that was an invalid command!")

start()

所以基本上,当用户完成转换时,我希望它循环回到顶部.我仍然无法将循环示例付诸实践,因为每次我使用def函数循环时,它都表示“op”未定义.

解决方法:

与大多数现代编程语言一样,Python不支持“goto”.相反,您必须使用控制功能.基本上有两种方法可以做到这一点.

1.循环

您可以如何完成SmallBasic示例的操作示例如下：

while True :
    print "Poo"

就这么简单.

2.递归

def the_func() :
   print "Poo"
   the_func()

the_func()

关于递归的注意事项：只有在您想要返回到开头的特定次数时才执行此操作(在这种情况下,在递归应该停止时添加一个案例).像我上面定义的那样进行无限递归是一个坏主意,因为你最终会耗尽内存！

编辑更具体地回答问题

#Alan's Toolkit for conversions

invalid_input = True
def start() :
    print ("Welcome to the converter toolkit made by Alan.")
    op = input ("Please input what operation you wish to perform. 1 for Fahrenheit to Celsius, 2 for meters to centimetres and 3 for megabytes to gigabytes")
    if op == "1":
        #stuff
        invalid_input = False # Set to False because input was valid


    elif op == "2":
        #stuff
        invalid_input = False # Set to False because input was valid
    elif op == "3": # you still have this as "if"; I would recommend keeping it as elif
        #stuff
        invalid_input = False # Set to False because input was valid
    else:
        print ("Sorry, that was an invalid command!")

while invalid_input : # this will loop until invalid_input is set to be True
    start()

标签：python-3-3,python
来源： https://codeday.me/bug/20190917/1809320.html