javascript – jqGrid(v4.1.2)treegrid的排序不能与Ajacency Model一起使用
作者:互联网
我一直在使用jqGrid,关于Adjacency模型有一些useful questions和answers,除了排序,我已经得到了我需要连接和工作的所有东西.
问题实际上是在上面的答案链接中复制的.谁能看到需要修理的东西?奥列格似乎是这方面的专家!
我已尝试过question中的选项,但我认为当前版本(4.1.2)可能有新错误?请证明我错了.
我也在http://trirand.com/blog/jqgrid/jqgrid.html>上看到了这个例子. 3.4的新内容>树网格邻接模型可以工作,但该示例未使用loaded:true属性,如本问题的first referenced answer中所述
解决方法:
你是对的.这是我之前回答的数据中的小错误
经过一些调试后我发现错误非常简单:一个应该使用parent:“null”或parent:null而不是parent:“”.
此外,您必须在网格中定义sorttype参数,以便正确排序其他任何数据作为文本.
现在如何正确地看到the modified demo支持本地排序:
首先是按所选列对根元素进行排序,然后递归所有子节点.
为了便于在搜索引擎中找到新代码,我在下面包含了演示代码:
var mydata = [
{id: "1", name: "Cash", num: "100", debit: "400.00", credit: "250.00", balance: "150.00", enbl: "1", level: "0", parent: "null", isLeaf: false, expanded: false, loaded: true},
{id: "2", name: "Cash 1", num: "1", debit: "300.00", credit: "200.00", balance: "100.00", enbl: "0", level: "1", parent: "1", isLeaf: false, expanded: false, loaded: true},
{id: "3", name: "Sub Cash 1", num: "1", debit: "300.00", credit: "200.00", balance: "100.00", enbl: "1", level: "2", parent: "2", isLeaf: true, expanded: false, loaded: true},
{id: "4", name: "Cash 2", num: "2", debit: "100.00", credit: "50.00", balance: "50.00", enbl: "0", level: "1", parent: "1", isLeaf: true, expanded: false, loaded: true},
{id: "5", name: "Bank\'s", num: "200", debit: "1500.00", credit: "1000.00", balance: "500.00", enbl: "1", level: "0", parent: "null", isLeaf: false, expanded: true, loaded: true},
{id: "6", name: "Bank 1", num: "1", debit: "500.00", credit: "0.00", balance: "500.00", enbl: "0", level: "1", parent: "5", isLeaf: true, expanded: false, loaded: true},
{id: "7", name: "Bank 2", num: "2", debit: "1000.00", credit: "1000.00", balance: "0.00", enbl: "1", level: "1", parent: "5", isLeaf: true, expanded: false, loaded: true},
{id: "8", name: "Fixed asset", num: "300", debit: "0.00", credit: "1000.00", balance: "-1000.00", enbl: "0", level: "0", parent: "null", isLeaf: true, expanded: false, loaded: true}
],
grid = $("#treegrid");
$.jgrid.formatter.integer.thousandsSeparator=',';
$.jgrid.formatter.number.thousandsSeparator=',';
$.jgrid.formatter.currency.thousandsSeparator=',';
grid.jqGrid({
datatype: "jsonstring",
datastr: mydata,
colNames: [/*"Id", */"Account", "Acc Num", "Debit", "Credit", "Balance", "Enabled"],
colModel: [
//{name: 'id', index: 'id', width: 1, hidden: true, key: true},
{name: 'name', index: 'name', width: 180},
{name: 'num', index: 'acc_num', width: 80, formatter: 'integer', sorttype: 'int', align: 'center'},
{name: 'debit', index: 'debit', width: 80, formatter: 'number', sorttype: 'number', align: 'right'},
{name: 'credit', index: 'credit', width: 80, formatter: 'number', sorttype: 'number', align: 'right'},
{name: 'balance', index: 'balance', width: 80, formatter: 'number', sorttype: 'number', align: 'right'},
{name: 'enbl', index: 'enbl', width: 60, align: 'center',
formatter: 'checkbox', editoptions: {value: '1:0'},
formatoptions: {disabled: false}}
],
height: 'auto',
gridview: true,
rowNum: 10000,
sortname: 'id',
treeGrid: true,
treeGridModel: 'adjacency',
treedatatype: "local",
ExpandColumn: 'name',
caption: "Demonstrate how to use Tree Grid for the Adjacency Set Model",
jsonReader: {
repeatitems: false,
root: function (obj) { return obj; },
page: function () { return 1; },
total: function () { return 1; },
records: function (obj) { return obj.length; }
}
});
标签:javascript,jquery,sorting,jqgrid,treegrid 来源: https://codeday.me/bug/20190916/1808262.html