boost python wrap c类私有成员

我们可以用boost python包装c私有构造函数吗？
我有一个单例c类,并希望将其包装到python.

我们可以用boost python包装c私有成员函数吗？

非常感谢

解决方法:

使用这样的东西：

#include <boost/python.hpp>
#include <iostream>

using namespace boost::python;
using std::cout;

class Singleton
{
    private:
        Singleton()
        {
            cout << "Creating instance\n";
        }
    friend Singleton* create(); 
};

Singleton* pInstance_;
Singleton* create()
{       
    if(!pInstance_)
    {
        pInstance_ = new Singleton();
    }
    else
    {
        cout << "Using old instance\n";         
    }       
    return pInstance_;
}

BOOST_PYTHON_MODULE(cppmodule)
{
    def("create", create, return_value_policy<reference_existing_object>());
    class_<Singleton>("Singleton", no_init);
}

/* using singleton later in code */

Singleton* otherInstance_ = create();

会议：

>>> import cppmodule
Creating instance
>>> s = cppmodule.Singleton()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
RuntimeError: This class cannot be instantiated from Python
>>> s = cppmodule.create()
Using old instance

标签：boost-python,python,c,boost
来源： https://codeday.me/bug/20190831/1776878.html