PHP / Laravel存储库模式,创建“复杂”对象的正确逻辑

使用存储库模式来处理“复杂”对象的逻辑,来回…
顺便说一下,我正在使用Laravel框架.

好的,我在数据库中有这些表：

>用户
>公司
> company_translations
> company_contacts
> company_files

关系：
– 用户与公司有一对一的多态性(我有更多类型的用户,如管理员和客户)
– 公司有one-many with company_translations(公司的某些属性可以翻译成多种语言)
– 公司有一对多与company_contacts
– 公司有one-many with company_files

我有一个CompanyController和一个CompanyRepository.我试图把所有的创造逻辑
公司在CompanyRepository中,而不是使用公司其他部分的回购(联系人,文件,翻译).

因此,例如,当管理员创建公司时,控制器从包含所有数据的表单接收信息(还有一个表单请求,负责验证输入,典型规则)
关于公司(核心,翻译,文件,联系人),然后它会将该数据传递给repo函数,如：

$company = $this->companyRepository->create($data);

我的问题在于该函数,我如何构造/验证传递给函数的数据？它必须在表公司中创建一个条目,一个用于用户,一个或多个用于翻译,一个或多个用于联系人,0个或更多用于文件.

例如,来自有关翻译的请求的输入组织如下：

companyDescription['en']
companyDescription['es']
companyDescription['pt']
etc

回购不应该知道它的结构,对吧？我是否在控制器内执行此操作,例如：

$userData = [
  'email'    => $request->input('email'),
  'password' => $request->input('password'),
  etc
];

$companyData = [
  'company_name' => $request->input('companyName'),
  'company_slug' => $request->input('companySlug'),
  etc 
];

然后将这些变量传递给repo函数？此外,还需要一些字段,因此并非所有数据都是必需的,即文件不是必需的.
我如何链接所有必要的步骤？
或者我以完全不同的方式处理这个问题？

正确理解这一逻辑让我感到紧张……欢迎所有解决方案.

希望我很清楚/ – 解释我有什么,问题是什么.哦,我想坚持使用存储库模式;)

解决方法:

为了记录,表格溢出：

array: [▼

  "active" => "1"
  "highlighted" => "0"
  "jobOffersApproved" => "1"
  "trainingCoursesApproved" => "1"
  "email" => ""
  "password" => ""
  "password_confirmation" => ""
  "companyName" => ""
  "companyDescription" => array:3 [▼
    "pt" => ""
    "en" => ""
    "es" => ""
  ]
  "businessSector" => ""
  "fiscalNumber" => ""
  "website" => ""
  "linkedin" => ""
  "facebook" => ""
  "twitter" => ""
  "googleplus" => ""
  "country" => ""
  "district" => ""
  "county" => ""
  "location" => ""
  "address" => ""
  "postalCode" => ""
  "phone" => ""
  "cellphone" => ""
  "fax" => ""
  "mainContact" => array:3 [▼
    "firstName" => ""
    "lastName" => ""
    "email" => ""
  ]
  "jobOffersContact" => array:3 [▼
    "firstName" => ""
    "lastName" => ""
    "email" => ""
  ]
  "trainingCoursesContact" => array:3 [▼
    "firstName" => ""
    "lastName" => ""
    "email" => ""
  ]
]

“用户”表将收到此信息：

array: [▼
  "active" => "1"
  "email" => ""
  "password" => ""
]

“公司”表：

array: [▼
  "highlighted" => "0"
  "jobOffersApproved" => "1"
  "trainingCoursesApproved" => "1"
  "companyName" => ""
  "businessSector" => ""
  "fiscalNumber" => ""
  "website" => ""
  "linkedin" => ""
  "facebook" => ""
  "twitter" => ""
  "googleplus" => ""
  "country" => ""
  "district" => ""
  "county" => ""
  "location" => ""
  "address" => ""
  "postalCode" => ""
  "phone" => ""
  "cellphone" => ""
  "fax" => ""
]

“company_contacts”表：

每个数组条目都是表中的一行.只有“mainContact”是强制性的.

array: [▼
  "mainContact" => array:3 [▼
    "firstName" => ""
    "lastName" => ""
    "email" => ""
  ]
  "jobOffersContact" => array:3 [▼
    "firstName" => ""
    "lastName" => ""
    "email" => ""
  ]
  "trainingCoursesContact" => array:3 [▼
    "firstName" => ""
    "lastName" => ""
    "email" => ""
  ]
]

此外,应该有一个来自表单的文件,关于公司徽标,这不是强制性的,并且会转到“company_files”表.

标签：php,repository-pattern,laravel
来源： https://codeday.me/bug/20190711/1429287.html