javascript – 将Json数据加载到jqPlot中

我对JSON和jqPlot有疑问.

jQuery脚本：

var line = [ ];
$(function(){
    $.getJSON('bin/gielda.php', function(data) {
        $.each(data, function (index, value) {
            line.push(["'"+data[index].data+"'",data[index].kurs_odn]);         
        }); 
        console.log(line);
    });
    $.jqplot('chartdiv', [line], {
        title :' Giełda',
        axes : {
            xaxis : {
                renderer : $.jqplot.DateAxisRenderer
            }
        },
        series : [{
            lineWidth : 4,
            markerOptions : {
                style : 'square'
            }
        }]
    });
});

来自gielda.php的php：

$pdo = new PDO('mysql:host=localhost;dbname=gielda', 'root', '');
$pdo -> setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = $pdo -> prepare("SELECT  data,kurs_odn FROM template WHERE nazwa=?");
$sql -> execute(array("ASSECOPOL"));
$gielda = $sql->fetchAll(PDO::FETCH_ASSOC);
echo json_encode($gielda);

php文件的结果如下：

[{"data":"2010-08-19","kurs_odn":"55.75"},{"data":"2010-08-19","kurs_odn":"55.75"},{"data":"2010-08-19","kurs_odn":"55.75"},{"data":"2010-08-20","kurs_odn":"56.2"},{"data":"2010-08-20","kurs_odn":"56.2"},{"data":"2010-08-20","kurs_odn":"56.2"}]

变量行的Console.log：

[["'2010-08-19'", "55.75"], ["'2010-08-19'", "55.75"], ["'2010-08-19'", "55.75"], ["'2010-08-20'", "56.2"], ["'2010-08-20'", "56.2"], ["'2010-08-20'", "56.2"]]

和错误：未捕获的异常：[object Object]

解决方法:

我可能找到了解决方案.
起初$.jqplot必须在$.getJSON里面 – 我忘记了JavaScript中的异步调用代码.

我不必要地在数据[index] .data中添加了引号

line.push(["'"+data[index].data+"'",data[index].kurs_odn]); 

但我必须添加Number(data [index] .kurs_odn)因为默认情况下是字符串.
现在看来工作正常.

标签：jquery,javascript,jqplot
来源： https://codeday.me/bug/20190705/1383797.html