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反转附加列表或添加列表是否更便宜? – Python

作者:互联网

哪个更快更pythonic?

>反转附加列表
>从头开始预先开始列表
>使用deque

例如.这是用于存储到新列表中的ome组成数据

# Let's say my function outputs these output individually.
x = [12,34,44,346,345,876,123]

反转附加列表:

new_list = []
for i in x:
  new_list.append(i)
new_list = newlist[::-1]

在列表前面:

new_list = [] 
for i in x:
  new_list.insert(0,i)

使用deque:

from collections import deque
for i in x:
  x.appendleft(i)

请注意,我的问题不是如何反转列表.还请假设列表大小约为20,000.

解决方法:

您的第一种方法可以简化为一行:

new_list = x[::-1]

然后,要检查哪个方法比任何其他方法更快,只需使用timeit(使用python 2.7.8测试):

C:\>python -m timeit -s "x = [12,34,44,346,345,876,123]" "new_list = x[::-1]"
1000000 loops, best of 3: 0.215 usec per loop

C:\>python -m timeit -s "x = [12,34,44,346,345,876,123]; new_list = []" "for i in x:" "  new_list.insert(0,i)"
10000 loops, best of 3: 146 usec per loop

C:\>python -m timeit -s "from collections import deque; x = [12,34,44,346,345,876,123]; new_list = deque()" "for i in x:" "  new_list.appendleft(i)"
1000000 loops, best of 3: 0.713 usec per loop

C:\>python -m timeit -s "x = [12,34,44,346,345,876,123]" "new_list = list(reversed(x))"
1000000 loops, best of 3: 0.837 usec per loop

所以new_list = x [:: – 1]比任何其他方式都要好.

您还必须问自己是否要“引用”或“复制”元素到新的列表结构中.

标签:python,insert,reverse,list,prepend
来源: https://codeday.me/bug/20190703/1363598.html