coding:utf-8

from timeit import timeit

def count_append():
lists = []
for x in range(0, 100000):
lists.append(x)

cost_time = timeit(stmt=count_append, number=1)
print("append花费的时间是", cost_time)

def count_extend():
lists = []
for x in range(0, 100000):
list1 = [x]
lists.extend(list1)

cost_time = timeit(stmt=count_extend, number=1)
print("extend花费的时间为", cost_time)

def count_insert():
lists = []
for x in range(0, 100000):
lists.insert(x, x)

cost_time = timeit(stmt=count_insert, number=1)
print("insert花费的时间为", cost_time)

def count_plus():
lists = []
for x in range(0, 100000):
list1 = [x]
lists = lists+list1

cost_time = timeit(stmt=count_plus, number=1)
print("plus花费的时间为", cost_time)

append花费的时间是 0.008006025272567989

extend花费的时间为 0.010472806737249051

insert花费的时间为 0.012643240513279762

plus花费的时间为 13.00245008582025

由此可得append是耗时最短的

标签：count,timeit,python,lists,列表,插入方法,cost,time,append
来源： https://www.cnblogs.com/dxxpython/p/10995399.html