实验五 函数程序设计
作者:互联网
1、
#include "stdafx.h" #include "math.h" int add (int a,int b){ int c; c=a+b; return c; } int minus (int a,int b){ int c; c=a-b; return c; } int multip (int a,int b){ int c; c=a*b; return c; } int quotient (int a,int b){ int c; c=a/b; return c; } int mod (int a,int b){ int c; c=a%b; return c; } int main(int argc, char* argv[]) { int x,y; scanf("%d %d",&x,&y); int d1,d2,d3,d4,d5; d1=add(x,y); d2=minus(x,y); d3=multip(x,y); d4=quotient(x,y); d5=mod(x,y); printf("%d\n%d\n%d\n%d\n%d\n",d1,d2,d3,d4,d5); return 0; }
2、
#include "stdafx.h" #include "math.h" int prime(int n){ int i,j; j=n; for(i=2;i<j;i++){ if(n%i==0){ return 0; } else if(n%i!=0){ return 1; } } } int main(int argc, char* argv[]) { int a; scanf("%d",&a); prime(a); if (prime(a)==0) printf("No\n"); else printf("Yes\n"); return 0; }
3、
#include "stdafx.h" #include "math.h" int max2(int x,int y){ int z; z=x>y?x:y; return z; } int max4(int x,int y,int m,int n){ int z; max2(x,y); int i; i=m>n?m:n; int j; j=z>i?z:i; return j; } int main(int argc, char* argv[]) { int x,y,m,n; int max; scanf("%d %d %d %d",&x,&y,&m,&n); max=max4(x,y,m,n); printf("max is %d",max); return 0; }
4、
#include "stdafx.h" #include "math.h" int rec(int n){ int y; if(n==0||n==1||n==2) return n; else return n*rec(n-1); } int main(int argc, char* argv[]) { int n,sum; scanf("%d",&n); sum=rec(n); printf("%d",sum); return 0; }
标签:return,函数,int,max,实验,stdafx,程序设计,include,math 来源: https://www.cnblogs.com/P201821440042/p/10967893.html