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c# – Expression-Bodied函数在get-property中使用的成员

作者:互联网

在编写类时,我可以通过两种方式在Get-property中使用Expression bodied函数:

class Person
{
    public string FirstName {get; set;}
    public string LastName {get; set;}

   public string FullName1 => $"{FirstName} {LastName}";
   public string FullName2 { get => $"{FirstName} {LastName}"; }
}

MSDN约expression bodied function members

You can also use expression-bodied members in read-only properties as
well:

public string FullName => $"{FirstName} {LastName}";

因此,如果此语法表示Get属性的实现,那么第二个是什么意思?有什么不同?一个优先于另一个吗?

解决方法:

那些是相同的.他们编译成相同的代码:

Person.get_FullName1:
IL_0000:  ldstr       "{0} {1}"
IL_0005:  ldarg.0     
IL_0006:  call        UserQuery+Person.get_FirstName
IL_000B:  ldarg.0     
IL_000C:  call        UserQuery+Person.get_LastName
IL_0011:  call        System.String.Format
IL_0016:  ret         

Person.get_FullName2:
IL_0000:  ldstr       "{0} {1}"
IL_0005:  ldarg.0     
IL_0006:  call        UserQuery+Person.get_FirstName
IL_000B:  ldarg.0     
IL_000C:  call        UserQuery+Person.get_LastName
IL_0011:  call        System.String.Format
IL_0016:  ret         

只是不同形式的表示法,允许您以相同的格式提供集合.

标签:c,c-6-0
来源: https://codeday.me/bug/20190527/1161827.html