javascript – 如何从我的汇总捆绑包中保留bower包依赖项？

我目前正在创建一个输出单个ES6模块的凉亭包.

在为我的包构建dist时,我使用汇总将所有内部模块移动到单个模块中,仅导出一个模块.

Gulp任务：

// Bundle ES6 modules into a single file
gulp.task('bundle', function(){
  return gulp.src('./src/GuacaMarkdownEditor.js', {read: false})
    .pipe(rollup({
        // any option supported by rollup can be set here, including sourceMap
        // https://github.com/rollup/rollup/wiki/JavaScript-API
        format: 'es6',
        sourceMap: true
    }))
    .pipe(sourcemaps.write(".")) // this only works if the sourceMap option is true
    .pipe(gulp.dest('./dist'));
});

这一切都运行正常,但我从其他bower包导入一些依赖项,我不想与我的模块捆绑(jQuery,font-awesome).

我的问题是：如何保持捆绑我的代码并保留bower包的ES6导入语句 – 但是没有汇总将外部代码捆绑到我的包中？

例：

"use strict";

import $from 'jquery'; // dont bundle this!
import GuacaAirPopUp from './GuacaAirPopUp'; // bundle this!

export
default class GuacaMarkdownEditor {

  ...

}

解决方法:

您可以使用此汇总插件rollup-plugin-includepaths.

它允许您按名称导入模块,并且应该从捆绑包中排除定义模块.我在rollup.config.js中使用它：

import babel from 'rollup-plugin-babel'; 
import includePaths from 'rollup-plugin-includepaths'; 

var includePathOptions = { 
    paths: ['es6'], 
    include: { 
      'd3': './global/js/' + 'base/d3.min'  // include library in es6 modules
    },   
    external: ['d3'] // but don't bundle them into bundle.js
};

export default { 
 entry: './es6/entry.js', 
 plugins: [ 
 includePaths(includePathOptions), 
 babel() 
 ], 
 format: 'amd', 
 dest: 'build/bundle.js', 
 sourceMap: true 
 };

在es6模块中：

// not using relative path since it is handled by the plugin
import d3 from 'd3';
import other from 'otherModules'; 
//...

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标签：javascript,ecmascript-6,bower,gulp,rollupjs
来源： https://codeday.me/bug/20190519/1136179.html