C++ 时间字符串的格式化输出
作者:互联网
1.Linux系统函数 gettimeofday, 毫秒级时间戳,需要包含头文件 #include <sys/time.h>
static std::string getCurrentTime()
{
struct timeval tv;
gettimeofday(&tv, NULL);
static constexpr size_t MAX_BUFFER_SIZE = 128;
char buff[MAX_BUFFER_SIZE + 1];
time_t sec = static_cast<time_t>(tv.tv_sec);
int ms = static_cast<int>(tv.tv_usec) / 1000;
struct tm tm_time;
localtime_r(&sec, &tm_time);
static const char *formater = "%4d-%02d-%02d %02d:%02d:%02d.%03d";
int ret = snprintf(buff, MAX_BUFFER_SIZE, formater,
tm_time.tm_year + 1900, tm_time.tm_mon + 1, tm_time.tm_mday,
tm_time.tm_hour, tm_time.tm_min, tm_time.tm_sec, ms);
if (ret < 0) {
return std::string("");
}
return std::string(buff);
}
2.使用C++标准库函数 std::chrono
static std::string FormatTimePoint(const std::chrono::system_clock::time_point &time_point,
const std::string &format = "%Y-%m-%d %X")
{
auto in_time_t = std::chrono::system_clock::to_time_t(time_point);
std::stringstream ss;
ss << std::put_time(std::localtime(&in_time_t), format.c_str());
return ss.str();
}
使用方法如下:
int main()
{
// 方法一
std::cout << getCurrentTime() << std::endl;
// 方法二
const std::chrono::time_point<std::chrono::system_clock> now =
std::chrono::system_clock::now();
std::cout << FormatTimePoint(now) << std::endl;
return 0;
}
结果输出:
2022-03-25 12:17:57.336
2022-03-25 12:17:57
Process finished with exit code 0
标签:std,02d,格式化,tv,C++,tm,static,time,字符串 来源: https://www.cnblogs.com/sunwenqi/p/16054076.html