Educoder：python实验七 元组和集合

1. 日期的转换

   x=input("输入日期")
   #开始
   date = {1:'January',2:'February',3:'March',4:'April',5:'May',6:'June',7:'July',8:'August',9:'September',10:'October',11:'November',12:'December'}
   k = x.split('/')
   m = date.get(int(k[1]))
   y = m+' '+k[2]+','+k[0]
   z = k[2]+' '+m+','+k[0]
   #结束
   print("美式格式"+y)
   print("英式格式"+z)
   

2. 计算购买饮品金额

   cp=(("悠哉悠哉",18),("人间烟火",17),("蔓越阑珊",17),("抹茶葡提",16),("幽兰拿铁",16),("  翠翠  ",13),("浮生半日",15),("筝筝纸鸢",16),("声声乌龙",15),("风栖绿桂",12),("素颜锡兰",13),("烟火易冷",15))
   #代码开始
   k = 1
   c = 0
   for i in range(len(cp)):
       if k<10:
           z = ' '+str(k)
       else:
           z = str(k)
       for j in range(len(cp[0])):
           z += str(cp[i][j])
       print(z)
       k += 1
   while True:
       a = int(input("请选择饮品"))
       if a == 0:
           break
       b = int(input("请输入数量"))
       c += cp[a-1][1]*b
   print("应付"+str(c)+"元")
   #代码结束
   

3. 判断句子是否每个英文字母起码出现一次

   x=input("")
   #代码开始
   a = set(x)
   b = set('QWERTYUIOPASDFGHJKLZXCVBNMqwertyuiopasdfghjklzxcvbnm')
   c = a&b
   if len(c)>=24:
       print('True')
   else:
       print('False')
   
   #代码结束
   

4. 集合的运算

   hd1=set()
   hd2=set()
   gh=input("")
   lb=gh.split(',')
   for x in lb:
       hd1.add(eval(x))
   gh=input("")
   lb=gh.split(',')
   for x in lb:
       hd2.add(eval(x))
   #代码开始
   hd3 = hd1&hd2
   hd4 = hd1-hd2
   hd5 = hd2-hd1
   #代码结束
   print("两项活动都参加",hd3)
   print("只参加活动1",hd4)
   print("只参加活动2",hd5)
   

标签：Educoder,lb,hd2,hd1,python,元组,print,input,gh
来源： https://blog.csdn.net/weixin_45821514/article/details/121834442