挺强的算24程序，支持2重()

# 1-((2+3)*4) = -19
ptns = '''N?N?N?N
N?N?N?N
N?N?(N?N)
N?(N?N)?N
N?(N?N?N)
N?(N?(N?N))
N?((N?N)?N)
(N?N?N)?N
(N?(N?N))?N
((N?N)?N)?N'''.splitlines()
def permute(x):
    def pmt(x, y, n, i):
        if i == n: yield y
        for j in range(n):
            if x[j] == 99: continue
            y[i] = s = x[j]; x[j] = 99
            yield from pmt(x, y, n, i + 1)
            x[j] = s
    n = len(x)
    return pmt(x, list(range(n)), n, 0) 

x = ('1 2 3 4' if 1 else input()).split()
if len(x) != 4: exit()
for n_ in permute(x):
  for p_ in permute(['+', '-', '*']):
      for t in ptns:
          e = ''; n = n_.copy(); p = p_.copy()
          for u in t:
              if u == '?': e += p.pop()
              elif u == 'N': e += n.pop()
              else:    e += u
          print(e, '=', eval(e))

N?N?(N?N)可是自动生成滴：

import ply.lex as lex # pip install ply
import ply.yacc as yacc
from functools import reduce
tokens = ('WORD',); t_WORD = r'[\w+\+\-\*\/\(\)\?]'; literals = (':', ';')
t_ignore  = ' \t\r\n'
def t_error(t): raise SyntaxError()
d = {}
def p_1(p): "rules : rule"
def p_2(p): "rules : rule rules"
def p_4(p):
    "rule : WORD ':' words ';'"
    k = p[1]; v = d.get(k, []); v.append([p[3]])
    d[k] = v
def p_5(p): "words : WORD"; p[0] = [p[1]]
def p_6(p): "words : WORD words"; p[0] = [p[1]] + p[2]
lexer = lex.lex()
istr = '''
    e : N ;
    e : N ? e ;
    e : N ? (e) ;
    e : (e) ? N ;
'''
try:
    yacc.yacc().parse(istr)
except SyntaxError: quit()
seen = set()
def gen(s):
    if len(s) > 11: return
    expanded = False
    for i in range(len(s)):
        w = s[i]
        for r in d.get(w, []):
            expanded = True
            gen(s[:i] + r[0] + s[i + 1:])
    e = reduce(lambda a,b:a+b, s)
    if e in seen: return
    seen.add(e)
    if not expanded:
        if e.count('?') == 3: print(e)
gen(['e'])

我吹了一点牛。(N)我干不掉，于是串替换成N，再一看有重复的，手工删掉了。

标签：24,WORD,挺强,程序,len,yacc,words,lex,def
来源： https://www.cnblogs.com/funwithwords/p/15651550.html