python将英文单词表示的数字转换成阿拉伯数字的代码

下边内容内容是关于python将英文单词表示的数字转换成阿拉伯数字的内容。
import re
_known = {
‘zero’: 0,
‘one’: 1,
‘two’: 2,
‘three’: 3,
‘four’: 4,
‘five’: 5,
‘six’: 6,
‘seven’: 7,
‘eight’: 8,
‘nine’: 9,
‘ten’: 10,
‘eleven’: 11,
‘twelve’: 12,
‘thirteen’: 13,
‘fourteen’: 14,
‘fifteen’: 15,
‘sixteen’: 16,
‘seventeen’: 17,
‘eighteen’: 18,
‘nineteen’: 19,
‘twenty’: 20,
‘thirty’: 30,
‘forty’: 40,
‘fifty’: 50,
‘sixty’: 60,
‘seventy’: 70,
‘eighty’: 80,
‘ninety’: 90
}
def spoken_word_to_number(n):
“”“Assume n is a positive integer”.
assert _positive_integer_number(‘nine hundred’) == 900
assert spoken_word_to_number(‘one hundred’) == 100
assert spoken_word_to_number(‘eleven’) == 11
assert spoken_word_to_number(‘twenty two’) == 22
assert spoken_word_to_number(‘thirty-two’) == 32
assert spoken_word_to_number(‘forty two’) == 42
assert spoken_word_to_number(‘two hundred thirty two’) == 232
assert spoken_word_to_number(‘two thirty two’) == 232
assert spoken_word_to_number(‘nineteen hundred eighty nine’) == 1989
assert spoken_word_to_number(‘nineteen eighty nine’) == 1989
assert spoken_word_to_number(‘one thousand nine hundred and eighty nine’) == 1989
assert spoken_word_to_number(‘nine eighty’) == 980
assert spoken_word_to_number(‘nine two’) == 92 # wont be able to convert this one
assert spoken_word_to_number(‘nine thousand nine hundred’) == 9900
assert spoken_word_to_number(‘one thousand nine hundred one’) == 1901
“”"

n = n.lower().strip()
if n in _known:
    return _known[n]
else:
    inputWordArr = re.split('[ -]', n)

assert len(inputWordArr) > 1 #all single words are known
#Check the pathological case where hundred is at the end or thousand is at end
if inputWordArr[-1] == 'hundred':
    inputWordArr.append('zero')
    inputWordArr.append('zero')
if inputWordArr[-1] == 'thousand':
    inputWordArr.append('zero')
    inputWordArr.append('zero')
    inputWordArr.append('zero')
if inputWordArr[0] == 'hundred':
    inputWordArr.insert(0, 'one')
if inputWordArr[0] == 'thousand':
    inputWordArr.insert(0, 'one')

inputWordArr = [word for word in inputWordArr if word not in ['and', 'minus', 'negative']]
currentPosition = 'unit'
prevPosition = None
output = 0
for word in reversed(inputWordArr):
    if currentPosition == 'unit':
        number = _known[word]
        output += number
        if number > 9:
            currentPosition = 'hundred'
        else:
            currentPosition = 'ten'
    elif currentPosition == 'ten':
        if word != 'hundred':
            number = _known[word]
            if number < 10:
            else:
                output += number
        #else: nothing special
        currentPosition = 'hundred'
    elif currentPosition == 'hundred':
        if word not in [ 'hundred', 'thousand']:
            number = _known[word]
            currentPosition = 'thousand'
        elif word == 'thousand':
            currentPosition = 'thousand'
        else:
            currentPosition = 'hundred'
    elif currentPosition == 'thousand':
        assert word != 'hundred'
        if word != 'thousand':
            number = _known[word]
    else:
        assert "Can't be here" == None

return(output)

标签：inputWordArr,word,python,阿拉伯数字,number,assert,spoken,英文单词,hundred
来源： https://blog.csdn.net/weixin_44099735/article/details/121006777